The reagent used in the conversion of the following reaction is:

 

1.	\(\mathrm{NaBH}_4 \)	2.	\(\mathrm{LiAlH}_4 \)
3.	\(PCC \)	4.	\(\mathrm{KMnO}_4\)

Identify the major product,

1.     

2.   

3.    

4. 

$\stackrel{{\mathrm{LiAlH}}_4}{\to }$(A) Major; Product (A) is:   

(a) 

(b) 

(c) 

(d) 

$\stackrel{{\mathrm{H}}_2{\mathrm{CrO}}_4}{\to }$(A) Product (A) is:   

(a) No reaction

(b) 

(c) 

(d) 

Consider the following alcohols,

(I)  (II) 

(III) (IV) 

The order of decreasing reactivities of these alcohols towards nucleophilic substitution with HBr is:-

(a) III>I>IV>II

(b) III>I>II>IV

(c) I>III>IV>II

(d) I>III>II>IV

The structure of A in the below mentioned reaction is:

 

1.		2.
3.		4.

$\underset{\left(2\right)<mspace\; width="1em"></mspace>{\mathrm{H}}^{+},<mspace\; width="1em"></mspace>{\mathrm{H}}_2\mathrm{O}<mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace>}{\overset{\left(1\right)<mspace\; width="1em"></mspace>\mathrm{EtLi}<mspace\; width="1em"></mspace>(3.5<mspace\; width="1em"></mspace>\mathrm{eq})}{\to }}<mspace\; width="1em"></mspace>\left(\mathrm{A}\right)<mspace\; width="1em"></mspace>65\%<mspace\; width="1em"></mspace>\mathrm{Yield}<mspace\; width="1em"></mspace>$; Chemist added extra 0.5 mole of Et-Li in above reaction to obtain product (A), which is ?

What is the major product (A) in the following reaction?

1.		2.
3.		4.

Which is the best reagent to convert isopropyl alcohol to isopropyl bromide ?

 $<mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace>C{H}_3<mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace>C{H}_3$
$<mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace>|<mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace>|$
$C{H}_3-CH-OH\stackrel{?}{\to }<mspace\; width="1em"></mspace>C{H}_3-CH-Br$

(1) HBr

(2) SOBr₂

(3) Br₂

(4) CH₃MgBr