# NEET Physics Current Electricity Questions Solved

PMT - 2000

The internal resistance of a cell of e.m.f. 12V is $5×{10}^{-2}\text{\hspace{0.17em}}\Omega$. It is connected across an unknown resistance. Voltage across the cell, when a current of 60 A is drawn from it, is

(1) 15 V

(2) 12 V

(3) 9 V

(4) 6 V

(3) $V=E-ir$ = $12-60×5×{10}^{-2}$ = 9V.

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