The internal resistances of two cells shown are 0.1 Ω and 0.3 Ω. If R = 0.2 Ω, the potential difference across the cell

(1) B will be zero

(2) A will be zero

(3) A and B will be 2V

(4) A will be > 2V and B will be < 2V

(1) Applying Kirchhoff law

(2+2)=(0.1+0.3+0.2)ii=203A

Hence potential difference across A

=20.1×203=43V (less than 2V)

Potential difference across B=20.3×203=0 

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