A wire has a resistance of 6 Ω. It is cut into two parts and both half values are connected in parallel. The new resistance is ....

(1) 12 Ω

(2) 1.5 Ω

(3) 3 Ω

(4) 6 Ω

(2) Given $R=6\Omega$.

When resistor is cut into two equal parts and connected in parallel, then

${R}_{eq}=\frac{R/2}{2}=\frac{R}{4}=\frac{6}{4}=1.5\text{\hspace{0.17em}}\Omega$

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