In the figure, current through the 3 Ω resistor is 0.8 ampere, then potential drop through 4 Ω resistor is 

1. 9.6 V

2. 2.6 V

3. 4.8 V

4. 1.2 V

What is the equivalent resistance between A and B in the figure below if R = 3 Ω 

1. 9 Ω

2. 12 Ω

3. 15 Ω

4. None of these

What is the equivalent resistance between A and B 

1. $\frac{2}{3}R$

2. $\frac{3}{2}R$

3. $\frac{R}{2}$

4. 2 R

What is the equivalent resistance of the circuit​​​​​?

1. \(6~\Omega\)
2. \(7~\Omega\)
3. \(8~\Omega\)
4. \(9~\Omega\)

In the given figure, the equivalent resistance between the points A and B is :

1. 8 Ω

2. 6 Ω

3. 4 Ω

4. 2 Ω

A battery of emf 10 V and internal resistance 3 Ω is connected to a resistor as shown in the figure. If the current in the circuit is 0.5 A. then the resistance of the resistor will be 

1. 19 Ω

2. 17 Ω

3. 10 Ω

4. 12 Ω

The potential drop across the 3Ω resistor is 

1. 1 V

2. 1.5 V

3. 2 V

4. 3 V

If each resistance in the figure is \(9~\Omega\), then the reading of the ammeter is:

1. \(5~\text{A}\)
2. \(8~\text{A}\)
3. \(2~\text{A}\)
4. \(9~\text{A}\)

Two wires of equal diameters, of resistivities ρ₁ and ρ₂ and lengths l₁ and l₂, respectively, are joined in series. The equivalent resistivity of the combination is :

1. $\frac{{\rho }_1{l}_1+{\rho }_2{l}_2}{l_1+l_2}$

2. $\frac{{\rho }_1{l}_2+{\rho }_2{l}_1}{l_1-l_2}$

3. $\frac{{\rho }_1{l}_2+{\rho }_2{l}_1}{l_1+l_2}$

4. $\frac{{\rho }_1{l}_1-{\rho }_2{l}_2}{l_1-l_2}$