NEET Physics Current Electricity Questions Solved

PMT - 1997

In the circuit shown below, the cell has an e.m.f. of 10 V and internal resistance of 1 ohm. The other resistances are shown in the figure. The potential difference VAVB is 

(1) 6 V

(2) 4 V

(3) 2 V

(4) –2 V

(4) Equivalent external resistance of the given circuit Req=4Ω

Current given by the cell i=EReq+r=10(4+1)=2A

Hence, (VAVB)=i2×(R2R1)=22(24)=2V. 

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