NEET Questions Solved


A particle moves in the xy-plane under the action of a force F such that the components of its linear momentum p at any time t are px=2cost, py=2sint. The angle between F and p at time t is 

(1) 90°

(2) 0°

(3) 180°

(4) 30°

(1) Given that p=pxi^+pyj^=2costi^+2sintj^

F=dpdt=2sinti^+2costj^

Now, F.p=0 i.e. angle between F and pis 90°. 

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