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A particle moves in the xy-plane under the action of a force F such that the components of its linear momentum p at any time t are px=2cost, py=2sint. The angle between F and p at time t is
(1) Given that p→=pxi^+pyj^=2cost i^+2sint j^
∴ F→=dp→dt=−2sint i^+2cost j^
Now, F→.p→=0 i.e. angle between F→ and p→ is 90°.