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A body is given motion from rest to move in a straight line. If an opposite force then obstructs it, then:

1. The body may necessarily change direction
2. The body is sure to slow down
3. The body will necessarily continue to move in the same direction at the same speed
4. None of these

Subtopic:  Newton's Laws |
 76%
Level 2: 60%+
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Two balls of masses \(m_1\) and \(m_2\) are separated from each other by a powder charge placed between them. The whole system is at rest on the ground. Suddenly, the powder charge explodes, and the masses are pushed apart. The mass \(m_1\) travels a distance \(s_1\) and stops. If the coefficients of friction between the balls and the ground are the same, the mass \(m_2\) stops after travelling the distance:

1. \(s_2=\dfrac{m_1}{m_2}s_1\)

2. \(s_2=\dfrac{m_2}{m_1}s_1\)

3. \(s_2=\dfrac{(m_1)^2}{(m_2)^2}s_1\)

4. \(s_2=\dfrac{(m_2)^2}{(m_1)^2}s_1\)

Subtopic:  Friction |
Level 3: 35%-60%
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A force vector applied to a mass is represented as \(\vec F=6\hat i−8\hat j+10\hat k\) and accelerates it with \(1\ \text{m/s}^2\). The mass of the body will be:

1. \(10\sqrt 2\ \text{kg}\)
2. \(2\sqrt {10}\ \text{kg}\)
3. \(10\ \text{kg}\)
4. \(20\ \text{kg}\)

Subtopic:  Application of Laws |
 86%
Level 1: 80%+
PMT - 1996
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A cricket ball of mass \(250\ \text{g}\) collides with a bat with velocity \(10\ \text{m/s}\) and returns with the same velocity within \(0.01\) second. The force acted on the bat is:

1. \(25\ \text{N}\)
2. \(50\ \text{N}\)
3. \(250\ \text{N}\)
4. \(500\ \text{N}\)

Subtopic:  Newton's Laws | Application of Laws |
 63%
Level 2: 60%+
PMT - 1997
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A pendulum bob of mass \(50\ \text{g}\) is suspended from the ceiling of an elevator. The tension in the string if the elevator goes up with uniform velocity is approximately:

1. \(0.30\ \text{N}\)
2. \(0.40\ \text{N}\)
3. \(0.42\ \text{N}\)
4. \(0.50\ \text{N}\)

Subtopic:  Application of Laws |
 89%
Level 1: 80%+
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The average force necessary to stop a bullet of mass 20 g moving with a speed of 250 m/s, as it penetrates into the wood for a distance of 12 cm is 

1. 2.2 × 103 N

2. 3.2 × 103 N

3. 4.2 × 103 N

4. 5.2 × 103 N

Subtopic:  Newton's Laws |
 71%
Level 2: 60%+
PMT - 2000
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A man measures the time period of a pendulum \((T)\) in a stationary lift. If the lift moves upward with acceleration \(\dfrac g4\) then the new time period will be:

1. \(\dfrac {2T} {\sqrt5}\)

2. \(\dfrac {\sqrt5T} {2}\)

3. \(\dfrac {\sqrt5} {2T}\)

4. \(\dfrac {2}{\sqrt5T} \)

Subtopic:  Application of Laws |
 73%
Level 2: 60%+
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If the rope of the lift breaks suddenly, the tension exerted by the surface of the lift \((a = \text{acceleration of lift})\):

1. \(mg\)
2. \(m(g + a)\)
3. \(m(g – a)\)
4. \(0\)

Subtopic:  Application of Laws |
 65%
Level 2: 60%+
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A lift of mass \(1000\ \text{kg}\) is moving with an acceleration of \(1\ \text{m/s}^2\) in the upward direction. The tension developed in the string, which is connected to the lift, is:

1. \(9,800\ \text{N}\)

2.  \(10,000\ \text{N}\)

3. \(10,800\ \text{N}\)

4.  \(11,000\ \text{N}\)

Subtopic:  Application of Laws |
 50%
Level 3: 35%-60%
PMT - 2002
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A lift is accelerating vertically downward with acceleration (\(a\)). A man inside the lift moves a ball upward with acceleration \(a_0\) relative to the lift, where \( (a_0 < a)\). What is the acceleration of the ball as observed by a stationary observer on the ground?

1. \((a + a_0)\) upward

2. \((a - a_0)\) upward

3. \((a + a_0)\) downward

4. \((a - a_0)\) downward

Subtopic:  Application of Laws |
 50%
Level 3: 35%-60%
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