A stone is thrown at an angle θ to the horizontal reaches a maximum height H. Then the time of flight of stone will be 

(1) 2Hg

(2) 22Hg

(3) 22Hsinθg

(4) 2Hsinθg

Concept Videos :-

#11-Projectile-Motion-1
#12-Projectile-Examples
#13-Projectile-Motion-2
#14-Projectile-Examples-1
#15-Projectile-Examples-2
#16-Solved-Examples-3
#17-Projectile-Examples-4
#18-Maximum-Height
#20-Derivation-of-Equation-of-Trajectory
#21-Solved-Examples-11

Concept Questions :-

Projectile motion

(2) H=u2sin2θ2g and T=2usinθgT2=4u2sin2θg2

T2H=8gT=8Hg=22Hg 

Difficulty Level:

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