In a projectile motion, velocity at maximum height is

(1) $\frac{u\text{\hspace{0.17em}}\mathrm{cos}\text{\hspace{0.17em}}\theta }{2}$

(2) $u\text{\hspace{0.17em}}\mathrm{cos}\text{\hspace{0.17em}}\theta$

(3) $\frac{u\text{\hspace{0.17em}}\mathrm{sin}\text{\hspace{0.17em}}\theta }{2}$

(4) None of these

Concept Questions :-

Projectile motion
High Yielding Test Series + Question Bank - NEET 2020

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The equation of motion of a projectile are given by x = 36 t metre and 2y = 96 t – 9.8 t2 metre. The angle of projection is

(1) ${\mathrm{sin}}^{-1}\left(\frac{4}{5}\right)$

(2) ${\mathrm{sin}}^{-1}\left(\frac{3}{5}\right)$

(3) ${\mathrm{sin}}^{-1}\left(\frac{4}{3}\right)$

(4) ${\mathrm{sin}}^{-1}\left(\frac{3}{4}\right)$

Concept Questions :-

Projectile motion
High Yielding Test Series + Question Bank - NEET 2020

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For a given velocity, a projectile has the same range R for two angles of projection. If t1 and t2 are the times of flight in the two cases then :

(1) ${t}_{1}{t}_{2}\propto \text{\hspace{0.17em}}{R}^{2}$

(2) ${t}_{1}{t}_{2}\propto \text{\hspace{0.17em}}R$

(3) ${t}_{1}{t}_{2}\propto \text{\hspace{0.17em}}\frac{1}{R}$

(4) ${t}_{1}{t}_{2}\propto \text{\hspace{0.17em}}\frac{1}{{R}^{2}}$

Concept Questions :-

Projectile motion
High Yielding Test Series + Question Bank - NEET 2020

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A body of mass m is thrown upwards at an angle θ with the horizontal with velocity v. While rising up the velocity of the mass after t seconds will be

(1) $\sqrt{{\left(v\text{\hspace{0.17em}}\mathrm{cos}\text{\hspace{0.17em}}\theta \right)}^{2}+{\left(v\text{\hspace{0.17em}}\mathrm{sin}\text{\hspace{0.17em}}\theta \right)}^{2}}$

(2) $\sqrt{{\left(v\text{\hspace{0.17em}}\mathrm{cos}\text{\hspace{0.17em}}\theta -v\mathrm{sin}\text{\hspace{0.17em}}\theta \right)}^{2}-\text{\hspace{0.17em}}gt}$

(3) $\sqrt{{v}^{2}+{g}^{2}{t}^{2}-\left(2\text{\hspace{0.17em}}v\text{\hspace{0.17em}}\mathrm{sin}\text{\hspace{0.17em}}\theta \right)\text{\hspace{0.17em}}gt}$

(4) $\sqrt{{v}^{2}+{g}^{2}{t}^{2}-\left(2\text{\hspace{0.17em}}v\text{\hspace{0.17em}}\mathrm{cos}\text{\hspace{0.17em}}\theta \right)\text{\hspace{0.17em}}gt}$

Concept Questions :-

Projectile motion
High Yielding Test Series + Question Bank - NEET 2020

Difficulty Level:

A cricketer can throw a ball to a maximum horizontal distance of 100 m. With the same effort, he throws the ball vertically upwards. The maximum height attained by the ball is

(1) 100 m

(2) 80 m

(3) 60 m

(4) 50 m

Concept Questions :-

Projectile motion
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A ball is projected with velocity V0 at an angle of elevation 30°. Mark the correct statement

(1) Kinetic energy will be zero at the highest point of the trajectory

(2) Vertical component of momentum will be conserved

(3) Horizontal component of momentum will be conserved

(4) Gravitational potential energy will be minimum at the highest point of the trajectory

Concept Questions :-

Projectile motion
High Yielding Test Series + Question Bank - NEET 2020

Difficulty Level:

Neglecting the air resistance, the time of flight of a projectile is determined by

(1) Uvertical

(2) Uhorizontal

(3) U = U2vertical + U2horizontal

(4) U = U(U2vertical + U2horizontal )1/2

Concept Questions :-

Projectile motion
High Yielding Test Series + Question Bank - NEET 2020

Difficulty Level:

A ball is thrown from a point with a speed v0 at an angle of projection θ. From the same point and at the same instant a person starts running with a constant speed v0/2 to catch the ball. Will the person be able to catch the ball? If yes, what should be the angle of projection?

1. Yes, 60°

2. Yes, 30°

3. No

4. Yes, 45°

Concept Questions :-

Projectile motion
High Yielding Test Series + Question Bank - NEET 2020

Difficulty Level:

A stone is thrown at an angle θ to the horizontal reaches a maximum height H. Then the time of flight of stone will be

(1) $\sqrt{\frac{2H}{g}}$

(2) $2\text{\hspace{0.17em}}\sqrt{\frac{2H}{g}}$

(3) $\frac{2\sqrt{2H\text{\hspace{0.17em}}\mathrm{sin}\theta }}{g}$

(4) $\frac{\sqrt{2H\text{\hspace{0.17em}}\mathrm{sin}\theta }}{g}$

Concept Questions :-

Projectile motion
High Yielding Test Series + Question Bank - NEET 2020

Difficulty Level:

The horizontal range of a projectile is $4\sqrt{3}$ times its maximum height. Its angle of projection will be

(1) 45°

(2) 60°

(3) 90°

(4) 30°

Concept Questions :-

Projectile motion