A projectile thrown with a speed v at an angle θ has a range R on the surface of earth. For same v and θ, its range on the surface of moon will be (acceleration due to gravity on moon=$\frac{g}{6}$):

(1) R/6

(2) 6 R

(3) R/36

(4) 36 R

Concept Videos :-

#11-Projectile-Motion-1
#12-Projectile-Examples
#13-Projectile-Motion-2
#14-Projectile-Examples-1
#15-Projectile-Examples-2
#16-Solved-Examples-3
#17-Projectile-Examples-4
#18-Maximum-Height
#20-Derivation-of-Equation-of-Trajectory
#21-Solved-Examples-11

Concept Questions :-

Projectile motion

(2) Range is given by $R=\frac{{u}^{2}\mathrm{sin}2\theta }{g}$

On moon ${g}_{m}=\frac{g}{6}$. Hence Rm = 6 R

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