A particle is projected with velocity ${v}_{0}$ along x-axis. The deceleration on the particle is proportional to the square of the distance from the origin i.e., $a=\alpha {x}^{2}.$ The distance at which the particle stops is

(1) $\sqrt{\frac{3{v}_{0}}{2\alpha }}$

(2) ${\left(\frac{3{v}_{o}}{2\alpha }\right)}^{\frac{1}{3}}$

(3) $\sqrt{\frac{3v{}_{0}{}^{2}}{2\alpha }}$

(4) ${\left(\frac{3v{}_{0}{}^{2}}{2\alpha }\right)}^{\frac{1}{3}}$

Concept Videos :-

#42 Non Uniform Acceleration
#43 Solved Examples 29
#44 Solved Examples 30

Concept Questions :-

Non-uniform acceleration
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