The position x of a particle varies with time t as $x=a{t}^{2}-b{t}^{3}$. The acceleration of the particle will be zero at time t equal to

(1) $\frac{a}{b}$

(2) $\frac{2a}{3b}$

(3) $\frac{a}{3b}$

(4) Zero

Concept Questions :-

Acceleration
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Difficulty Level:

If a train travelling at 72 kmph is to be brought to rest in a distance of 200 metres, then its retardation should be

(1) 20 ms–2

(2) 10 ms–2

(3) 2 ms–2

(4) 1 ms–2

Concept Questions :-

Uniformly accelerated motion
High Yielding Test Series + Question Bank - NEET 2020

Difficulty Level:

The displacement of a particle starting from rest (at t = 0) is given by $s=6{t}^{2}-{t}^{3}$. The time in seconds at which the particle will attain zero velocity again, is

(1) 2

(2) 4

(3) 6

(4) 8

Concept Questions :-

Instantaneous speed and instantaneous velocity
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Difficulty Level:

Two cars A and B are at rest at same point initially. If A starts with uniform velocity of 40 m/sec and B starts in the same direction with constant acceleration of 4 m/s2, then B will catch A after how much time ?

(1) 10 sec

(2) 20 sec

(3) 30 sec

(4) 35 sec

Concept Questions :-

Instantaneous speed and instantaneous velocity
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Difficulty Level:

The motion of a particle is described by the equation $x=a+b{t}^{2}$ where a = 15 cm and b = 3 cm/s2. Its instantaneous velocity at time 3 sec will be

(1) 36 cm/sec

(2) 18 cm/sec

(3) 16 cm/sec

(4) 32 cm/sec

Concept Questions :-

Instantaneous speed and instantaneous velocity
High Yielding Test Series + Question Bank - NEET 2020

Difficulty Level:

A body travels for 15 sec starting from rest with constant acceleration. If it travels distances S1, S2 and S3 in the first five seconds, second five seconds and next five seconds respectively the relation between S1, S2 and S3 is

(1) ${S}_{1}={S}_{2}={S}_{3}$

(2) $5{S}_{1}=3{S}_{2}={S}_{3}$

(3) ${S}_{1}=\frac{1}{3}{S}_{2}=\frac{1}{5}{S}_{3}$

(4) ${S}_{1}=\frac{1}{5}{S}_{2}=\frac{1}{3}{S}_{3}$

Concept Questions :-

Uniformly accelerated motion
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Difficulty Level:

A body is moving according to the equation $x=at+b{t}^{2}-c{t}^{3}$ where x = displacement and a, b and c are constants. The acceleration of the body is

(1) $a+2bt$

(2) $2b+6ct$

(3) $2b-6ct$

(4) $3b-6c{t}^{2}$

Concept Questions :-

Acceleration
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Difficulty Level:

A particle travels 10m in first 5 sec and 10m in next 3 sec. Assuming constant acceleration what is the distance travelled in next 2 sec ?

(1) 8.3 m

(2) 9.3 m

(3) 10.3 m

(4) None of above

Concept Questions :-

Uniformly accelerated motion
High Yielding Test Series + Question Bank - NEET 2020

Difficulty Level:

The distance travelled by a particle is proportional to the squares of time, then the particle travels with

(1) Uniform acceleration

(2) Uniform velocity

(3) Increasing acceleration

(4) Decreasing velocity

Concept Questions :-

Uniformly accelerated motion
High Yielding Test Series + Question Bank - NEET 2020

Difficulty Level:

Velocity of a particle changes when

(1) Direction of velocity changes

(2) Magnitude of velocity changes

(3) Both of above

(4) None of the above

Concept Questions :-

Instantaneous speed and instantaneous velocity