We are given the following atomic masses:

U92238 = 238.05079 u, He24= 4.00260 u

Th90234 = 234.04363 u, H11= 1.00783 u

Pa91237= 237.05121 u

Here the symbol Pa is for the element protactinium (Z = 91).

The energy released during the alpha decay of U92238 is:

1. 6.14 MeV 

2. 7.68 MeV 

3. 4.25 MeV

4. 5.01 MeV 

Subtopic:  Nuclear Binding Energy |
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We are given the following atomic masses:

U92238 = 238.05079 u, He24= 4.00260 u

Th90234 = 234.04363 u, H11= 1.00783 u

Pa91237= 237.05121 u

Here the symbol Pa is for the element protactinium (Z = 91).

Then:

1. U92238 can not spontaneously emit a proton.

2. U92238 can spontaneously emit a proton.

3. The Q-value of the process is negative.

4. Both (1) and (3)

Subtopic:  Nuclear Binding Energy |
 61%
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The energy required in \(\mathrm{MeV} / \mathrm{c}^2\) to separate \({ }_8^{16} \mathrm{O}\) into its constituents is:
(Given mass defect for \({ }_8^{16} \mathrm{O}=0.13691 \mathrm{u}\))
1. \(127.5\)
2. \(120.0\)
3. \(222.0\)
4. \(119.0\)

Subtopic:  Mass-Energy Equivalent |
 68%
From NCERT
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The half-life of U92238 undergoing α-decay is 4.5×109 years. What is the activity of the 1g sample of U92238?

1. 2.11×104 Bq

2. 3.12×103 Bq

3. 1.23×104 Bq

4. 2.38×103 Bq

Subtopic:  Radioactivity (OLD NCERT) |
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Tritium has a half-life of 12.5 y undergoing beta decay. What fraction of a sample of pure tritium will remain undecayed after 25 y?
 

1. 18th
2. 14th
3. 13rd
4. 15th

Subtopic:  Radioactivity (OLD NCERT) |
 80%
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Which one of the following is incorrect?

1. A chemical equation is balanced in the sense that the number of atoms of each element is the same on both sides of the equation.
2. The number of atoms of each element is not necessarily conserved in a nuclear reaction.
3. The number of protons and the number of neutrons are conserved in each nuclear reaction.
4. Mass-energy interconversion takes place only in nuclear reactions and never in the chemical reaction.

Subtopic:  Nuclear Energy |
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Graph given below shows the variation of binding energy per nucleon, Ebn as a function of mass number. For nuclei with mass number A such that, 30 < A < 170, Ebn is almost constant because nuclear forces are:

 

1. Short-ranged 

2. Medium-ranged

3. Long-ranged

4. None of the above

Subtopic:  Nuclear Binding Energy |
 70%
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Graph gives the variation of potential energy of a pair of nucleons as a function of their separation, r. From the graph it can be concluded that the force between nucleons is attractive for distances:

   

1. Less than ro

2. Greater than ro

3. Less than ro2

4. Less than ro4

Subtopic:  Nuclear Binding Energy |
 57%
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The graph shows the exponential decay of a radioactive specie. The number of nuclei decayed after time t is:

 

1. Noe-λt
2. 2Noe-λt
3. No-Noe-λt
4. 2No-Noe-λt

Subtopic:  Radioactivity (OLD NCERT) |
 57%
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A nucleus with mass number \(240\) breaks into fragments each of mass number \(120\). The binding energy per nucleon of unfragmented nuclei is \(7.6\) MeV while that of fragments is \(8.5~\text{MeV}\). The total gain in the binding energy in the process is:


1. \(804\) MeV 
2. \(216\) MeV
3. \(0.9\) MeV
4. \(9.4\) MeV
Subtopic:  Nuclear Binding Energy |
 63%
From NCERT
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