The correct match is:
List-I List-II
a. Micro i.  10-15 m
b. Mega ii.  10-6 m
c. Giga iii.  106 m
d. Femto iv.  109 m
Codes:
a b c d
1. i iv iii ii
2. iii iv ii i
3. ii iii iv i
4. i iii iv ii

Subtopic:  Introduction |
 85%
Level 1: 80%+
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The incorrect statements regarding 1 mole of dioxygen gas at STP among the four statements is/are: 
(a) 16 g of gas
(b) 22.9 L of gas
(c) 6.022×1023 dioxygen molecules
(d) 11.2 L of gas
 
1. (a, b and c) 2. (a, b and d)
3. (b, c and d) 4. (a, c and d)
Subtopic:  Moles, Atoms & Electrons |
 71%
Level 2: 60%+
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The numbers 234,000 and 6.0012 can be represented in scientific notation as:
 

1. \(2.34 \times 10^{-9} \text { and } 6 \times 10^3\)
2. \(0.234 \times 10^{-6} \text { and } 60012 \times 10^{-9}\)
3. \(2.34 \times 10^{-9} \text { and } 6.0012 \times 10^{-9}\)
4. \(2.34 \times 10^5 \text { and } 6.0012 \times 10^0\)
Subtopic:  Introduction |
 84%
Level 1: 80%+
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The number of significant figures in the numbers 5005, 500.0, and 126,000 are, respectively: 
1. 2, 4, and 3 
2. 4, 1, and 3 
3. 4, 4, and 6 
4. 4, 4, and 3 
Subtopic:  Introduction |
 60%
Level 2: 60%+
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What is the difference between 0.50 mol Na₂CO₃ and 0.50 M Na₂CO₃?

1. They represent different amounts of Na₂CO₃.
2. 0.50 mol represents the amount of Na₂CO₃, whereas 0.50 M represents its molarity.
3. 0.50 mol Na₂CO₃ produces more ions.
4. None of the above.

Subtopic:  Introduction |
 89%
Level 1: 80%+
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Round up the following numbers into three significant figures: 
(i) 10.4107 
(ii) 0.04597

1. 10.4, 0.0460 2. 10.41, 0.046
3. 10.0, 0.04 4. 10.4, 0.0467
Subtopic:  Introduction |
 68%
Level 2: 60%+
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The following data was obtained when dinitrogen and dioxygen react together to form different compounds:

Mass of dinitrogen  Mass of dioxygen
i. 14 g 16 g
ii. 14 g 32 g
iii. 28 g 32 g
iv. 28 g 80 g

The law of chemical combination applicable to the above experimental data is:
1. Law of reciprocal proportions
2. Law of multiple proportions
3. Law of constant composition
4. None of the above.

Subtopic:  Introduction |
 75%
Level 2: 60%+
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An organic compound contains 80 % (by wt.) carbon and the remaining percentage of hydrogen. The empirical formula of this compound is:
[Atomic wt. of C is 12, H is 1] 
1. CH3
2. CH4
3. CH
4. CH2

Subtopic:  Empirical & Molecular Formula |
 77%
Level 2: 60%+
NEET - 2021
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The molecular formula of a commercial resin used for exchanging ions in water softening is C8H7SO3NaMol.Wt.206. The maximum uptake of Ca2+ ions by the resin when expressed in mole per gram resin is:
\( \mathrm{C}_8 \mathrm{H}_7 \mathrm{SO}_3 \mathrm{Na}+\mathrm{Ca}^{2+} \rightarrow (\mathrm{C}_8 \mathrm{H}_7 \mathrm{SO}_{3}){_2} \mathrm{Ca}+ \mathrm{Na}^{+}\)

1. 1103

2. 1206

3. 2309

4. 1412

Subtopic:  Moles, Atoms & Electrons |
Level 3: 35%-60%
Please attempt this question first.
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Please attempt this question first.

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Find the dimensionless (unitless) terms among the following concentration expressions.

 
(a) Molality (b) Molarity
(c) Mole fraction (d) Mass percent
Choose the correct option:
1. (a), (b) 2. (b), (c)
3. (a), (b), (c) 4. (c), (d)
Subtopic:  Concentration Based Problem |
Level 4: Below 35%
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