The difference between a weak field ligand and a strong field ligand is:

1. Weak field ligands cause higher splitting in the d orbitals than strong field ligands.
2. Weak field ligands cause lower splitting in the d orbitals than strong field ligands.
3. Strong field ligands do not form a complex with a metal ion.
4. None of the above.

Subtopic:  VBT, CFT & their Limitations |
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The crystal field splitting energy is:

1. The heat of formation between the two levels (e and t2) in tetrahedral splitting
2. The total pairing energy of the two levels (e and t2) in tetrahedral splitting.
3. The sum of the energy levels in an octahedral crystal field splitting.
4. The combined energy of the two levels (eg and t2g) in octahedral splitting.

Subtopic:  VBT, CFT & their Limitations |
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[Cr(NH3)6]3+ is paramagnetic ,while Ni(CN)42- is diamagnetic because:

1. Electrons in the 3d orbitals remain unpaired in Ni(CN)42-
2. Electrons in the 3d orbitals remain unpaired in [Cr(NH3)6]3+
3. Electrons in the 3p orbitals remain unpaired in [Cr(NH3)6]3+
4. Electrons in the 3p orbitals remain unpaired in Ni(CN)42-

Subtopic:  VBT, CFT & their Limitations |
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A solution of [Ni(H2O)6]2+ is green, but a solution of [Ni(CN)4]2– is colorless because:

1. There are paired electrons in [Ni(H2O)6]2+ while all electrons are unpaired in [Ni(CN)4]2–
2. There are unpaired electrons in [Ni(H2O)6]2+ while all electrons are paired in [Ni(CN)4]2–
3. There are unpaired electrons in [Ni(H2O)6]2+ and [Ni(CN)4]2–
4. None of the above.

Subtopic:  Introduction, Classification and Nomenclature |
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[Fe(CN)6]4– and [Fe(H2O)6]2+ are of different colors in dilute solutions because :

1. Higher lattice energy value of [Fe(CN)6]4– as compared to [Fe(H2O)6]2+
2. Higher CFSE value of [Fe(CN)6]4– as compared to [Fe(H2O)6]2+
3. Lower CFSE value of [Fe(CN)6]4– as compared to [Fe(H2O)6]2+
4. Lower lattice energy value of [Fe(CN)6]4– as compared to [Fe(H2O)6]2+

Subtopic:  Introduction, Classification and Nomenclature |
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The nature of bonding in metal carbonyls is -

1. The metal-carbon bonds in metal carbonyls have both σ and π characters.
2. The metal-carbon bonds in metal carbonyls have only σ character.
3. The metal-carbon bonds in metal carbonyls have only π character.
4. The metal-carbon bonds in metal carbonyls have only hydrogen bonding.
Subtopic:  Organometallic Complexes & their Uses |
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The greater value of the stability constant of complex salt indicates:

1. The greater proportion of products.

2. The greater proportion of reactants

3. Lesser concentration of catalyst at equilibrium

4. All of the above

Subtopic:  VBT, CFT & their Limitations |
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The correct order for the wavelengths of absorption in the visible region for the following is:
\(\left[\mathrm{Ni}\left(\mathrm{NO}_2\right)_6\right]^{4-},\left[\mathrm{Ni}\left(\mathrm{NH}_3\right)_6\right]^{2+},\left[\mathrm{Ni}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{2+}\)
1. [Ni(H2O)6]2+ < [Ni(NH3)6]2+ < [Ni(NO2)6]4-

2. [Ni(H2O)6]2+ > [Ni(NH3)6]2+ > [Ni(NO2)6]4-

3. [Ni(NH3)6]2+ > [Ni(H2O)6]2+> [Ni(NO2)6]4-

4.  [Ni(H2O)6]2+ > [Ni(NO2)6]4-> [Ni(NH3)6]2+

Subtopic:  VBT, CFT & their Limitations |
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The number of unpaired electrons in the following complexes respectively are-

K4[Mn(CN)6],Fe(H2O)6]2+,K2[MnCl4]

1. 1, 4, 5

2. 2, 4, 5

3. 0, 3, 4

4. 2, 3, 4

Subtopic:  VBT, CFT & their Limitations |
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Which of the following statements are correct?
a. Primary valencies are satisfied by negative ions while secondary valencies are satisfied by negative ion only. 
b. A metal ion has a definite number of secondary valencies around the central atom. 
c. Primary valencies are usually ionizable, while secondary valencies are non-ionizable
Choose the correct option:
1. a and b
2. a and c
3. b and c
4. a, b and c
Subtopic:  Werner’s Theory |
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