A particle is moving with veocity V=k(yi^+xj^); where k is constant. The general equation for path is:

1. y=x2+constant

2. y2=x2+constant

3. y=x+constant

4. xy=constant

 

Concept Questions :-

Speed and velocity
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A body thrown vertically so as to reach its maximum height in t second. The toal time from the time of projection to reach a point at half of its maximum height while returning (in second) is:

(1) 2t

(2) 1+12t

(3) 3t2

(4) t2

Concept Questions :-

Projectile motion
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A particle is projected with a velocity u making an angle θ with the horizontal. At any instant, its velocity V is at right angles to its initial velocity u; then V is:

1.  u cos θ

2.  u tan θ

3.  u cot θ

4.  u sec θ

Concept Questions :-

Projectile motion
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A projectile is given an initial velocity of i^+2j^. The cartesian equation of its path is (g = 10 ms-2

1. y=2x-5x2

2. y=x-5x2

3. 4y=2x-5x2

4. y=2x-25x2

Concept Questions :-

Projectile motion
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A ship A is moving westwards with a speed of 10 km h-1 and a ship B, 100 km south of A is moving northwards with a speed of 10 km h-1. The time after which the distance between them becomes the shortest, is:

1.  5 hr

2.  52 hr

3.  102 hr

4.  0 hr

Concept Questions :-

Relative motion
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Time taken by the projectile to reach from A to B is t. Then the distance AB is equal to :

1. ut3

2. 3ut2

3. 3ut

4. 2ut

Concept Questions :-

Projectile motion
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A particle projected with kinetic energy k0 with an angle of projection θ. Then the variation of kinetic K with vertical displacement y is

1.  linear

2.  parabolic

3.  hyperbolic

4.  periodic

Concept Questions :-

Projectile motion
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Three particles moving with constant velocities V1, V2 and V respectively as given in the figure. After some time all three particles are in the same line, then relation among V1, V2 and V is

                                     

1.  V = V1 + V2

2.  V = V1V2

3.  V = V1V2V1+V2

4.  V = 2V1V2V1+V2

Concept Questions :-

Speed and velocity
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A river is flowing with a speed of 1 km/hr. A swimmer wants to go to point 'C' starting from 'A'. He swims with a speed of 5 km/hr, at an angle θ w.r.t. the river. If AB=BC=400m. Then-

(1) time taken by the man is 12 min

(2) time taken by the man is 8 min

(3) the value of θ is 45°

(4) the value of θ is 53°

Concept Questions :-

Relative motion
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 A body is thrown horizontally with a velocity 2gh from the top of a tower of height h. It strikes the level ground through the foot of the tower at a distance x from the tower. The value of x is:

(1) h

(2) h2

(3) 2h

(4) 2h3

Concept Questions :-

Projectile motion
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