What is the maximum covalency exhibited by nitrogen?
1.Three (3)
2.Five (5)
3. Four (4)
4. Six (6)
Which of the following statements is false?
| 1. | Single N—N bond is stronger than the single P—P bond. |
| 2. | PH3 can act as a ligand in the formation of coordination compound with transition elements. |
| 3. | NO2 is paramagnetic in nature. |
| 4. | Covalency of nitrogen in N2O5 is four. |
A brown ring formed in the ring test for ion is due to the formation of:
1. [Fe(H2O)5(NO)]2+
2. FeSO4.NO2
3. [Fe(H2O)4(NO)2]2+
4. FeSO4.HNO3
Which of the following compounds contains bismuth in the +5 oxidation state?
1. \(\mathrm{Bi}_{2} \mathrm{O}_{5}\)
2. \(\mathrm{BiF}_{5}\)
3. \(\mathrm{BiCl}_{5}\)
4. \(\mathrm{Bi}_{2} \mathrm{~S}_{5}\)
Which of the following correctly represents the gaseous products formed on heating ammonium dichromate and barium azide, respectively?
| 1. | N2 in both cases. |
| 2. | N2 with ammonium dichromate and NO with barium azide. |
| 3. | N2O with ammonium dichromate and N2 with barium azide. |
| 4. | N2O with ammonium dichromate and NO2 with barium azide. |
How many moles of nitric oxide (NO) are formed when 2 moles of ammonia (NH₃) undergo oxidation?
1. Two (2)
2. Three (3)
3. Four (4)
4. Six (6)
Which of the following represents the oxidation state of the central atom in the hypophosphite ion, H₂PO₂⁻, present in NaH₂PO₂?
| 1. | +3 | 2. | +5 |
| 3. | +1 | 4. | -3 |
Which of the following species does not have a tetrahedral shape?
1. \(\mathrm{NH}_{4}^{+}\)
2. \(\mathrm{SiCl}_{4}\)
3. \(\mathrm{SF}_{4}\)
4. \(\mathrm{SO}_{4}^{2-}\)
Which of the following are peroxoacids of sulphur?
1. \(\mathrm{H}_{2} \mathrm{SO}_{5} \text { and } \mathrm{H}_{2} \mathrm{~S}_{2} \mathrm{O}_{8}\)
2. \(\mathrm{H}_{2} \mathrm{SO}_{5} \text { and } \mathrm{H}_{2} \mathrm{~S}_{2} \mathrm{O}_{7}\)
3. \(\mathrm{H}_{2} \mathrm{~S}_{2} \mathrm{O}_{7} \text { and } \mathrm{H}_{2} \mathrm{~S}_{2} \mathrm{O}_{8}\)
4. \(\mathrm{H}_{2} \mathrm{~S}_{2} \mathrm{O}_{6} \text { and } \mathrm{H}_{2} \mathrm{~S}_{2} \mathrm{O}_{7}\)
In the preparation of compounds of Xe, Bartlett had taken \(O_{2}^{+}PtF_{6}^{-}\) as a base compound. This is because:
1. Both and Xe have same size.
2. Both and Xe have same electron gain enthalpy.
3. Both and Xe have almost same ionisation enthalpy.
4. Both Xe and are gases.