A block of mass 2 kg is hanging with a massless spring and the spring is stretched by 40 cm. If the block is pulled down and released, then the period of oscillation is: (here, g = 10 m/s2)

1.  35π s

2.  52π s

3.  25π s

4.  53π s

Subtopic:  Combination of Springs |
 83%
From NCERT
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A spring is attached vertically to the ceiling of a lift and the lower end of spring is connected with a block of mass \(2~\text{kg}\). If the lift starts accelerating upwards with an acceleration \(2~\text{m/s}^2,\) then find the amplitude of SHM, while the spring constant is \(100~\text{N/m}\):
1. \(8~\text{cm}\)

2. \(1~\text{cm}\)

3. \(2~\text{cm}\)

4. \(4~\text{cm}\)

Subtopic:  Combination of Springs |
 62%
From NCERT
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The motion of the particle is started at t = 0 and the equation of motion is given by x = 8 sin100t + π6, where x is in cm and t is in seconds. When will the particle come to rest for the first time?

1.  π300 s

2.  π200 s

3.  π100 s

4.  π400 s

Subtopic:  Simple Harmonic Motion |
 59%
From NCERT
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What will be the frequency of oscillation of a simple pendulum, if the length of the pendulum is equal to the radius of earth?

1.  12πgR

2.  1πgR

3.  12π2gR

4.  12π3gR

Subtopic:  Angular SHM |
 56%
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The curve between the potential energy \((U)\) and displacement \((x)\) is shown. Which of the oscillation is about the mean position, \(x = 0?\)

1. 2.
3. 4.
Subtopic:  Energy of SHM |
 87%
From NCERT
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The time period of a body under S.H.M. is T1 and T2 when restoring forces F1 and F2 respectively act on it. What will be the time period of S.H.M. when both the forces act simultaneously on it?

1.  T1T2T1 + T2

2.  T1 + T2

3.  T1 + T2T1T2
4. \(\frac{\mathrm{T_1 T_2}}{\sqrt{\mathrm{T^2_1+T^2_2}}}\)

Subtopic:  Simple Harmonic Motion |
 55%
From NCERT
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A particle is subjected to two mutually perpendicular SHM such that x = 2sinωt and

y = 2 sinωt + π2The path of the particle will be

1.  An ellipse

2.  A straight line

3.  A parabola

4.  A circle

Subtopic:  Simple Harmonic Motion |
 59%
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Suppose that a pendulum clock is carried to a depth of 32 km inside the earth (Radius R = 6400 km). To have the correct time from the clock, by what percentage the effective length of the pendulum should be changed? 

1.  0.5%

2.  -0.5%

3.  1%

4.  -1.0%

Subtopic:  Simple Harmonic Motion |
 60%
From NCERT
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When a periodic force \(\vec{F_1}\) acts on a particle, the particle oscillates according to the equation \(x=A\sin\omega t\). Under the effect of another periodic force \(\vec{F_2}\), the particle oscillates according to the equation \(y=B\sin(\omega t+\frac{\pi}{2})\). The amplitude of oscillation when the force (\(\vec{F_1}+\vec{F_2}\)) acts are:

1. \(A+B\) 2. \(\sqrt{A^2+B^2}\)
3. \(\large\frac{\sqrt{A^2+B^2}}{2}\) 4. \(\sqrt{AB}\)
Subtopic:  Simple Harmonic Motion |
 91%
From NCERT
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A particle is executing SHM with amplitude A and angular frequency ω. The time taken by the particle to move from x = 0 to x = A/2 is

1.  π12 ω

2.  π6 ω

3.  π3 ω

4.  πω

Subtopic:  Simple Harmonic Motion |
 82%
From NCERT
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