The correct statement regarding the basicity of arylamines is

(1) Arylamines are generally more basic than alkylamines because the nitrogen lone-pair electrons are not delocalized by interaction with the aromatic ring p-electron system.

(2) Arylamines are generally more basic than alkylamines because of aryl group.

(3) Arylamines are generally more basic than alkylamines, because the nitrogen atom in arylamines is sp-hybridized

(4) Arylamines are generally less basic than alkylamines because the nitrogen lone-pair electrons are delocalized by interaction with the aromatic ring p-electron system.

Which of the following will be most stable diazonium salt $R{\mathrm{N}}_2^{+}{X}^{-}$ ?

(a) ${\mathrm{CH}}_3{\mathrm{N}}_2^{+}{\mathrm{X}}^{-}$

(b) ${\mathrm{C}}_6{\mathrm{H}}_5{\mathrm{N}}_2^{+}{\mathrm{X}}^{-}$

(c) ${\mathrm{CH}}_3{\mathrm{CH}}_2{\mathrm{N}}_2^{+}{\mathrm{X}}^{-}$

(d) ${\mathrm{C}}_6{\mathrm{H}}_5{\mathrm{CH}}_2{\mathrm{N}}_2^{+}{X}^{-}$

Which of the following is more basic than aniline ?

1. Diphenylamine

2. Triphenylamine

3. p-nitroaniline

4. Benzylamine

Which of the following compounds will not give Hoffmann bromamide reaction?

1.		2.
3.		4.

Identify the major product (A) formed in the following reaction/\.

1.               2.  

3.        4.  

Which of the following substituent as 'X' not decreases the rate of reaction with respect to aniline?

1.  

2.  $-{\mathrm{CH}}_3$

3.  $-{\mathrm{NO}}_2$

4.  -CHO

Which of the following compounds will give isocyanide test with ${\mathrm{CHCl}}_3/\mathrm{KOH}$?

1.  

2.  

3.  

4.  

Give the incorrect order of basic strength

1.  ${\mathrm{PhNH}}_2<\mathrm{PhNHMe}<{\mathrm{PhNMe}}_2$

2.  $\mathrm{p}-{\mathrm{CH}}_3{\mathrm{PhNH}}_2>\mathrm{m}-{\mathrm{CH}}_3{\mathrm{PhNH}}_2>{\mathrm{PhNH}}_2>\mathrm{o}-{\mathrm{CH}}_3{\mathrm{PhNH}}_2$

3.  ${\mathrm{PhNH}}_2>\mathrm{m}-{\mathrm{NO}}_2{\mathrm{PhNH}}_2>\mathrm{p}-{\mathrm{NO}}_2{\mathrm{PhNH}}_2>\mathrm{O}-{\mathrm{NO}}_2{\mathrm{PhNH}}_2$

4.  $\mathrm{o}-{\mathrm{CH}}_3{\mathrm{OPhNH}}_2>\mathrm{p}-{\mathrm{CH}}_3{\mathrm{OPHNH}}_2>{\mathrm{PhNH}}_2>\mathrm{m}-{\mathrm{CH}}_3{\mathrm{OPhNH}}_2$

For the following reaction

(major product) will be

1.  

2.  

3.  

4.  

A given nitrogen-containing aromatic compound a reacts with Sn/HCl, followed by HNO₂ to give an unsatable compound B.B, on treament with phenol, forms a beautiful coloured compound C with the molecular formula C₁₂H₁₀N₂O. The structure of compound A is