Water flows through a frictionless duct with a cross-section varying as shown in the figure. Pressure p at points along the axis is represented by:
         

1.		2.
3.		4.

Equation of continuity is based on:

An incompressible liquid travels as shown in the figure. The speed of the fluid in the lower branch will :

1. 1 m/s

2. 1.5 m/s

3. 2.25 m/s

4. 3 m/s

A wind with speed 40 m/s blows parallel to the roof of a house. The area of the roof is 250 m². Assuming that the pressure inside the house is atmospheric pressure, the force exerted by the wind on the roof and the direction of the force will be (P_air=1.2kg/m³)

1. 4.8x10⁵N,downwards

2. 4.8x10⁵N,upwards

3. 24x10⁵N,upwards

4. 24x10⁵N,downwards

Water rises to a height h in capillary tube . If the length of capillary tube is above the surface of water is made less than h, then

1. water rises upto the tip of capillary tube and then starts overflowing like a fountain

2. water rises upto the top of capillary tube and stays there without overflowing

3. water rises upto a point a little below the top and stays there

4. water does not rise at all

A piece of solid weighs 120 g in air, 80 g in water and 60 g in a liquid. The relative density of the solid and that of the liquid are respectively :

1. 3, 2

2. 2,$\frac{3}{4}$

3. $\frac{3}{2}$, 2

4. 3, $\frac{3}{2}$

An inverted bell lying at the bottom of a lake 47.6 m deep has 50 cm³ of air trapped in it. The bell is brought to the surface of the lake. The volume of the trapped air will be: (atmospheric pressure = 70 cm of Hg and density of Hg = 13.6 g/cm³) 

1. 350 cm³                               

2. 300 cm³

3. 250 cm³                               

4. 22 cm³

A siphon in use is demonstrated in the following figure. The density of the liquid flowing in the siphon is 1.5 gm/cc. The pressure difference between the point P and S will be:
            

The height of a mercury barometer is 75 cm at sea level and 50 cm at the top of a hill. The ratio of density of mercury to that of air is ${10}^4$. The height of the hill is:

A body of density d₁ is counterpoised by Mg of weights of density d₂ in air of density d. Then the true mass of the body is

1. M                                   

2. $\mathrm{M}\left(1-\frac{\mathrm{d}}{{\mathrm{d}}_2}\right)$

3. $\mathrm{M}\left(1-\frac{\mathrm{d}}{{\mathrm{d}}_1}\right)$                       

4. $\frac{\mathrm{M}(1-\mathrm{d}/{\mathrm{d}}_2)}{(1-\mathrm{d}/{\mathrm{d}}_1)}$