The angle of minimum deviation for a glass prism of refractive index \(\mu = \sqrt{3}\) equals the refracting angle of the prism. The angle of the prism is:
1. \(30^{\circ}\)
2. \(60^{\circ}\)
3. \(90^{\circ}\)
4. \(45^{\circ}\)$$

A diverging lens of focal length 20n cm and a converging mirror of focal length 10 cm are placed 5 cm apart coaxially. Where should an object be placed so that object and its real image coincide?

1. 20 cm away from the lens

2. 60 cm away from the lens

3. 30 cm away from the lens

4. 45 cm away from the lens

The minimum distance between a real object and screen such that a convex lens of focal length 20 cm can produce a real image on the screen is

1.  20 cm

2.  40 cm

3. 80 cm

4.  60 cm

A, B, and C are three optical media of respective critical angles ${\mathrm{i}}_{\mathrm{A}}, {\mathrm{i}}_{\mathrm{B}} \mathrm{and} {\mathrm{i}}_{\mathrm{C}}$. Total internal reflection of light can occur from A to B and also from B to C but not from C to A, then the correct relation between critical angles is 

1. $i_A<i_B<i_C$

2. $i_A>i_B>i_C$

3. $i_A=i_B=i_C$

4. $i_C>i_A>i_B$

The angle of prism for which there is no emergent ray will be($i_c$= critical angle)

1. $2i_c$

2. $>i_c$

3. $<i_c$

4. $>2i_c$

An optical element is shown in the figure. Radii of two surfaces are 10 cm and 20 cm. Calculate distance between two spherical surfaces so that image of the object coincides with the object itself

1.  100 cm

2.  80 cm

3.  110 cm

4.  95 cm

An object and a screen are fixed at a distance d apart. When a lens of focal length f is moved between the object and screen, sharp images of the object are formed on the screen for two positions of the lens. The Magnification produced at these two positions are ${\mathrm{M}}_1 \mathrm{and} {\mathrm{M}}_2$

1 $\overline{)\overline{){\mathrm{M}}_1}= } \overline{)\overline{)M_2} = 1}$

2. d > 4f

3. $M_1=\frac{1}{M_2}$

4. Both (2)& (3) are correct

An object O is placed on one side of two glass slabs A and B of thickness 1.5 cm and refractive index 1.5. The position of the image of O, when viewed from the other side of slab B, will be:

1.  1 cm away from slab A

2.  1.5 cm away from slab A

3.  2 cm away from slab A

4.  2.5 cm away from slab A

A virtual image of an object is formed by a concave lens. The lens is then coupled (kept in contact) with a convex lens. A virtual image is again formed. Then the image, now

1. Shifts away from lens system

2. Shifts towards lens system

3. Remains at its original position

4. Data are insufficient to predict whether it will shift towards or away from the lens system.

The correct statement is: