The major product in the following reaction is: 

1.		2.
3.		4.

 

Which of the following will not form a yellow precipitate on heating with an alkaline solution of iodine?

1. CH₃CH(OH)CH₃                                 

2. CH₃CH₂CH(OH)CH₃

3. CH₃OH                                               

4. CH₃CH₂OH

When propanoic acid is treated with aqueous sodium bicarbonate, CO₂ is liberated. The ‘C’ of CO₂ comes from:

1. Carboxylic acid group

2. Methylene group

3. Bicarbonate

4. Methyl group

A key step in the hydrolysis of acetamide in aqueous acid proceeds by nucleophilic addition of-

1. ${\mathrm{H}}_3{\mathrm{O}}^{+}$ to                          

2.  ${\mathrm{H}}_2\mathrm{O}$ to   

3. ${\mathrm{H}}_3{\mathrm{O}}^{+}$ to                          

4. ${\mathrm{HO}}^{-}$ to 

The product of the below mentioned reaction is- 

1.		2.
3.		4.

The main product X formed in the following reaction is

1.        2.  

3.    4.  

In the following reactions

1.  

2.  

3.  

4.  

In the given below reaction

x, y, and z are: 

1.  x = Mg; dry ether; y = ${\mathrm{CH}}_3\mathrm{Cl}; \mathrm{z} = {\mathrm{H}}_2\mathrm{O}$

2.  x = Mg; dry methanol; $\mathrm{y} = {\mathrm{CO}}_2; \mathrm{z} = \mathrm{dil}.\mathrm{HCl}$

3.  x = Mg; dry ether; $\mathrm{y} = {\mathrm{CO}}_2; \mathrm{z} = \mathrm{dil}.\mathrm{HCl}$

4.  x = Mg; dry methanol; $\mathrm{y} = {\mathrm{CH}}_3\mathrm{Cl}; \mathrm{z} = {\mathrm{H}}_2\mathrm{O}$

4-Formylbenzoic acid on treatment with one equivalent of hydrazine followed by heating with alcoholic KOH gives, as major product:

1.		2.
3.		4.

The major final product in the following reaction is

${\mathrm{CH}}_3{\mathrm{CH}}_2\mathrm{CN}\underset{\left(2\right){\mathrm{H}}_3{\mathrm{O}}^{+}}{\overset{\left(1\right){\mathrm{CH}}_3\mathrm{MgBr}}{\to }}$

1.        2.  

3.       4.