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The oxidation state of Cr in CrO6 is -

1. –6 2. +12
3. +6 4. +4

Subtopic:  Oxidizing & Reducing Agents |
 73%
Level 2: 60%+
NEET - 2019
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The standard electrode potential (E°) values of  Al3+/ Al,  Ag+ / Ag, K+ / K,  and Cr3+ / Cr are –1.66 V, 0.80 V, –2.93 V, & –0.79 V respectively. The correct decreasing order of the reducing power of the metal is:

1. Ag > Cr > Al > K 2. K > Al > Cr > Ag
3. K > Al > Ag > Cr 4. Al > K > Ag > Cr
Subtopic:  Emf & Electrode Potential |
 73%
Level 2: 60%+
NEET - 2019
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Among the following the correct order of acidity is-

1. HClO < HClO2< HClO3< HClO4
2. HClO2< HClO < HClO3< HClO4
3. HClO4< HClO2< HClO < HClO3
4. HClO3< HClO4< HClO2< HClO

Subtopic:  Oxidizing & Reducing Agents |
 87%
Level 1: 80%+
NEET - 2016
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Disproportionation reactions are:

(a) 2Cu+  Cu2++Cu0
(b) 3MnO42-+4H+  2MnO4-+MnO2+2H2O
(c) 2KMnO4  K2MnO4+MnO2+O2
(d) 2MnO4-+3Mn2++2H2O  5MnO2+4H

1. (a) and (d) only

2. (a) and (b) only

3. (a), (b) and (c)

4. (a), (c) and (d)

Subtopic:  Introduction to Redox and Oxidation Number |
 61%
Level 2: 60%+
NEET - 2019
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The number of moles of KMnO4 that will be needed to react with one mole of sulphite ion in an acidic solution is:

1. \(3 \over 5\) 2. \(4 \over 5\)
3. \(2 \over 5\) 4. 1
Subtopic:  Equivalent Weight |
 64%
Level 2: 60%+
AIPMT - 2007
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 FeCN64-FeCN63-+e-; Eo=-0.35 V
Fe2+Fe3++e-; Eo=-0.77 V
The strongest oxidizing agent in the above equation is:

1. FeCN64-

2. Fe2+

3. Fe3+

4. FeCN63-

Subtopic:  Emf & Electrode Potential |
 50%
Level 3: 35%-60%
AIPMT - 2008
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Oxidation numbers of P in PO43-, of S in SO42- and that of Cr in Cr2O72-are respectively:
1. +5, +6 and +6
2. +3, +6 and +5
3. +5, +3 and +6
4. -3, +6 and +6

Subtopic:  Oxidizing & Reducing Agents |
 91%
Level 1: 80%+
AIPMT - 2009
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The highest oxidation number of nitrogen among the following compounds is:

1. N2H4 2. NH3
3. N3H 4. NH2OH
Subtopic:  Oxidizing & Reducing Agents |
 63%
Level 2: 60%+
AIPMT - 2012
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The change in oxidation number of chlorine when Cl2 gas reacts with hot and concentrated sodium hydroxide solution is:

1. Zero to +1 and Zero to –5

2. Zero to –1 and Zero to +5

3. Zero to –1 and Zero to +3

4. Zero to +1 and Zero to –3

Subtopic:  Oxidizing & Reducing Agents |
 69%
Level 2: 60%+
AIPMT - 2012
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(a) H2O2 + O3 → H2O + 2O2 

(b) H2O2 + Ag2O → 2Ag + H2O + O2 

The role of hydrogen peroxide in the above reactions is respectively:

1.  Oxidizing in (a) and reducing in (b)
2.  Reducing in (a) and oxidizing in (b)
3.  Reducing in (a) and (b)
4.  Oxidizing in (a) and (b)

Subtopic:  Oxidizing & Reducing Agents |
 52%
Level 3: 35%-60%
AIPMT - 2014
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