A man weighing 80 kg is standing in a trolley weighing 320 kg. The trolley is resting on frictionless horizontal rails. If the man starts walking on the trolley with a speed of 1 m/s, then after 4 sec his displacement relative to the ground will be
1. 5 m
2. 4.8 m
3. 3.2 m
4. 3.0 m
A particle is projected at an angle \(𝜃
\) with the horizontal with an initial speed \(u\). When it makes an angle \(𝛼\) with the horizontal, its speed \(v\) is:
1. \(𝑢
\cos
𝜃\)
2. \(𝑢
\cos
𝜃
\ 𝑢
\cos
𝛼
\)
3. \(\dfrac{u\sin \theta}{\sin \alpha}\)
4. \(\dfrac{u\cos \theta}{\cos \alpha}\)
A particle is moving along the path y = from x = 0 m to x = 2 m. Then the distance traveled by the particle is:
1. 4 m
2.
3.
4.
Six particles situated at the corners of a regular hexagon of side \(a\) move at constant speed \(v\). Each particle maintains a direction towards the particle at the next. The time which the particles will take to meet each other is:
1. \(\dfrac{2 a}{v}\ \text{seconds}\)
2. \(\dfrac{a}{v}~\text{seconds}\)
3. \(\dfrac{2 a}{3v}~\text{seconds}\)
4. \(\dfrac{3 a}{v}~\text{seconds}\)
A body is projected with velocity \(20\sqrt3 \text{ m/s}\) with an angle of projection \(60^°\) with the horizontal. The velocity at the point where the body makes an angle \(30^° \)with the horizontal is:
1. \(20 \text{ m/s}\)
2. \(\dfrac{20}{\sqrt3} \text{ m/s}\)
3. \(10\sqrt3 \text{ m/s}\)
4. \(10 \text{ m/s}\)
In a uniform circular motion, which of the following quantity is not constant
1. Angular momentum
2. Speed
3. Kinetic energy
4. Momentum
A particle is moving with velocity \(\vec v=k(y\hat i+x \hat j)\), where \(k\) is constant. The general equation for the path is:
1. \(y=x^2+\text{constant}\)
2. \(y^2=x^2+\text{constant}\)
3. \(y=x+\text{constant}\)
4. \(xy=\text{constant}\)
A particle is projected with a velocity \(u\) making an angle \(θ\) with the horizontal. At any instant, its velocity \(v\) is at right angles to its initial velocity \(u\); then \(v\) is:
1. \(u \cos \theta \)
2. \(u \tan θ\)
3. \( u \cot θ\)
4. \(u \sec θ\)
A projectile is given an initial velocity of \(\hat i+2\hat j\). The cartesian equation of its path is: (Take \(g = 10 \ \text{ms}^{ - 2}\))
1. \(y=2x-5x^2\)
2. \(y=x-5x^2\)
3. \(4y=2x-5x^2\)
4. \(y=2x-25x^2\)
Ship A is moving westward with a speed of \(10\ \text{km h}^{- 1}\) and Ship B, south of A, is moving northwards with a speed of \(10\ \text{km h}^{- 1}\). The time after which the distance between them becomes the shortest is:
1. \(5\) hr
2. \(5 \sqrt2\) hr
3. \(10 \sqrt2\) hr
4. \(0\) hr