A battery is charged at a potential of 15V for 8h when the current flowing is 10A. The battery on discharge supplies a current of 5A for 15h. The mean terminal voltage during discharge is 14V. The 'watt-hour' efficiency of the battery is

1. 80%

2. 90%

3. 87.5%

4. 82.5%

 76%
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Five equal resistances each of resistance R are connected as shown in the figure. A battery of V volts is connected between A and B. The current flowing in AFCEB will be

1. VR

2. V2R

3. 2VR

4. 3VR

 50%
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Two batteries, one of emf 18 V and internal resistance 2Ω and the other of emf 12 V and internal resistance 1Ω, are connected as shown. The voltmeter V will record a reading of

1. 18 V

2. 30 V

3. 14 V

4. 15 V

 74%
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For the network shown in the figure, the value of the current i is

1. 18V5

2. 5V9

3. 9V35

4. 5V18

 75%
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Two cells, having the same emf, are connected in series through an external resistance R. Cells have internal resistances r1 and r2(r1>r2) respectively. When the circuit is closed, the potential difference across the first cell is zero. The value of R is

1. r1-r2

2. r1+r22

3. r1-r22

4. r1+r2

 58%
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The total power dissipated in Watts in the circuit shown here is

1. 4

2. 16

3. 30

4. 54

 87%
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An electric kettle takes 4A current at 220 V. How much time will it take to boil 1kg of water from temperature 20°C? The temperature of boiling water is 100°C .

1. 4.2 min

2. 6.3 min

3. 8.3 min

4. 12.6 min

 67%
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A cell can be balanced against 110 cm and 100 cm of the potentiometer wire, respectively with and without being short circuited through a resistance of 10Ω. Its internal resistance is

1. zero

2. 1.0Ω

3. 0.5Ω

4. 2.0Ω

 81%
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A wire of resistance 12  Ω is bent to form a complete circle of radius 10 cm. The resistance between its two diametrically opposite points, A and B as shown in the figure is

1. 3Ω

2. 6πΩ

3. 6Ω

4. 0.6πΩ

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See the electrical circuit shown in the figure below. Which of the following equations is a correct equation for it?

1.ε2-i2r2-ε1+i1r1=0

2. -ε2-(i1+i2)R+i2r2=0

3. ε1-(i1+i2)R+i1r1=0

4. ε1+(i1+i2)R-i1r1=0

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