Calculate the mass of 95% pure CaCO3 that will be required to neutralize 50 mL of 0.5 M HCl solution according to the following reaction.
CaCO3(s) + 2HCl(aq) → CaCl2(aq) + CO2(g) + 2H2O(l)
[Calculate up to the second place of decimal point]
CaCO3(s) + 2HCl(aq) → CaCl2(aq) + CO2(g) + 2H2O(l)
[Calculate up to the second place of decimal point]
| 1. | 9.50 g | 2. | 1.25 g |
| 3. | 1.32 g | 4. | 3.65 g |
Subtopic: Equation Based Problem |
54%
Level 3: 35%-60%
NEET - 2022
Hints
Identify the incorrect statement among the following options:
| 1. | \(O^+_2\) ion is diamagnetic. |
| 2. | The bond orders of \(O_2^{+},O_2,O^-_2\) and \(O_2^{2-}\) are 2.5, 2, 1.5, and 1, respectively. |
| 3. | \(C_2\) molecule has four electrons in its two degenerate \(\pi \) molecular orbitals. |
| 4. | \(H^+_2 \) ion has one electron. |
Subtopic: M.O.T |
79%
Level 2: 60%+
NEET - 2022
Hints
\(\mathrm{RMgX}+\mathrm{CO}_{2} \underset{\bf\text { ether }}{\stackrel{\bf\text { dry }}{\longrightarrow}} \mathrm{Y} \xrightarrow{{\mathrm{H}_{3} \mathrm{O}^{+}}}RCOOH\)
What is Y in the above reaction?
1. (RCOO)2Mg
2. RCOO-Mg+X
3. R3CO-Mg+X
4. RCOO-X+
What is Y in the above reaction?
1. (RCOO)2Mg
2. RCOO-Mg+X
3. R3CO-Mg+X
4. RCOO-X+
Subtopic: Carboxylic Acids: Preparation & Properties |
87%
Level 1: 80%+
NEET - 2022
Hints
Given below are half-cell reactions:
\(\text{MnO}_{4}^{-}+8 \text{H}^{+}+5 \text{e}^{-} \rightarrow \text{Mn}^{2+}+4 \text{H}_{2} \text{O}, \)
\( \text{E}_{\text{Mn}^{2+}}^{\circ} / \text{MnO}_{4}^{-}=-1.510 \text{ V} \)
\( \frac{1}{2} \text{O}_{2}+2 \text{H}^{+}+2 \text{e}^{-} \rightarrow \text{H}_{2} \text{O}, \)
\( \text{E}_{\text{O}_{2} / \text{H}_{2} \text{O}}^{\circ}=+1.223 \text{ V}\)
Will the permanganate ion, \(\text{MnO}_{4}^{-}\) , liberate \(\text{O}_{2}\) from water in the presence of an acid?
1. No, because \(\text{E}_{\text {cell }}^{\circ}=-2.733 \text{ V}\)
2. Yes, because \(\text{E}_{\text {cell }}^{\circ}=+0.287 \text{ V}\)
3. No, because \(\text{E}_{\text {cell }}^{\circ}=-0.287 \text{ V}\)
4. Yes, because \(\text{E}_{\text {cell }}^{\circ}=+2.733 \text{ V}\)
\(\text{MnO}_{4}^{-}+8 \text{H}^{+}+5 \text{e}^{-} \rightarrow \text{Mn}^{2+}+4 \text{H}_{2} \text{O}, \)
\( \text{E}_{\text{Mn}^{2+}}^{\circ} / \text{MnO}_{4}^{-}=-1.510 \text{ V} \)
\( \frac{1}{2} \text{O}_{2}+2 \text{H}^{+}+2 \text{e}^{-} \rightarrow \text{H}_{2} \text{O}, \)
\( \text{E}_{\text{O}_{2} / \text{H}_{2} \text{O}}^{\circ}=+1.223 \text{ V}\)
Will the permanganate ion, \(\text{MnO}_{4}^{-}\) , liberate \(\text{O}_{2}\) from water in the presence of an acid?
1. No, because \(\text{E}_{\text {cell }}^{\circ}=-2.733 \text{ V}\)
2. Yes, because \(\text{E}_{\text {cell }}^{\circ}=+0.287 \text{ V}\)
3. No, because \(\text{E}_{\text {cell }}^{\circ}=-0.287 \text{ V}\)
4. Yes, because \(\text{E}_{\text {cell }}^{\circ}=+2.733 \text{ V}\)
Subtopic: Electrode & Electrode Potential |
Level 3: 35%-60%
NEET - 2022
Hints
The given graph is a representation of the kinetics of a reaction.
The y and x axes for zero and first-order reactions, respectively are:
The y and x axes for zero and first-order reactions, respectively are:
| 1. | zero order (y=rate and x=concentration), first order (y=rate and x=t1/2) |
| 2. | zero order (y=concentration and x=time), first order (y=t1/2 and x = concentration) |
| 3. | zero order (y=concentration and x= time), first order (y=rate constant and x= concentration) |
| 4. | zero order (y=rate and x=concentration), first order (y=t1/2 and x = concentration) |
Subtopic: Order, Molecularity and Mechanism |
62%
Level 2: 60%+
NEET - 2022
Hints
Identify the statement that is incorrect regarding chirality:
| 1. | A racemic mixture shows zero optical rotation |
| 2. | SN1 reaction yields a 1:1 mixture of both enantiomers |
| 3. | The product obtained by SN2 reaction of haloalkane having chirality at the reactive site shows the inversion of configuration |
| 4. | Enantiomers are superimposable mirror images on each other |
Subtopic: Chemical Properties |
76%
Level 2: 60%+
NEET - 2022
Hints
The IUPAC name of an element with atomic number 119 is:
1. Ununoctium
2. Ununennium
3. Unnilennium
4. Unununnium
1. Ununoctium
2. Ununennium
3. Unnilennium
4. Unununnium
Subtopic: Modern Periodic Table & Periodicity |
83%
Level 1: 80%+
NEET - 2022
Hints
Given below are two statements:
In the light of the above statements, choose the most appropriate answer from the options given below:
1. Statement I is incorrect but Statement II is correct
2. Both Statement I and Statement II are correct
3. Both Statement I and Statement II are incorrect
4. Statement I is correct but Statement II is incorrect
| Statement I: | The boiling points of the following hydrides of group 16 elements increase in the order \(\mathrm{H}_{2} \mathrm{O}<\mathrm{H}_{2} \mathrm{~S}<\mathrm{H}_{2} \mathrm{Se}<\mathrm{H}_{2} \mathrm{Te} \) |
| Statement II: | The boiling points of these hydrides increase with the increase in molar mass. |
1. Statement I is incorrect but Statement II is correct
2. Both Statement I and Statement II are correct
3. Both Statement I and Statement II are incorrect
4. Statement I is correct but Statement II is incorrect
Subtopic: Group 16 - Preparation, Properties & Uses |
Level 3: 35%-60%
NEET - 2022
Hints
Which of the following species will exhibit the maximum lone pair–lone pair electron repulsions?
1. \(\mathrm{XeF_2}\)2. \(\mathrm{ClF_3}\)
3. \(\mathrm{IF_5}\)
4. \(\mathrm{SF_4}\)
Subtopic: V.S.E.P.R & V.B.T |
77%
Level 2: 60%+
NEET - 2022
Hints
For a first-order reaction A \(\rightarrow\) Products, initial concentration of A is 0.1 M, which becomes 0.001 M after 5 minutes. Rate constant for the reaction in min-1 is
| 1. | 0.2303 | 2. | 1.3818 |
| 3. | 0.9212 | 4. | 0.4606 |
Subtopic: First Order Reaction Kinetics |
72%
Level 2: 60%+
NEET - 2022
Hints
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