Find the correct reason for H₂O being polar while BeF₂ is non-polar.
| 1. | H₂O shows hydrogen bonding, whereas BeF₂ exists as a discrete molecule. |
| 2. | H₂O is linear, whereas BeF₂ is angular. |
| 3. | H₂O is angular, whereas BeF₂ is linear. |
| 4. | The electronegativity of F is greater than that of O |
Find the correct entropy condition for a spontaneous process.
1. ΔSsurroundings > 0 only2. ΔSsystem + ΔSsurroundings < 0
3. ΔSsystem > 0 only
4. ΔSsystem + ΔSsurroundings > 0
Ionic radii are:
| 1. | Inversely proportional to the square of effective nuclear charge. |
| 2. | Directly proportional to the effective nuclear charge. |
| 3. | Directly proportional to the square of effective nuclear charge. |
| 4. | Inversely proportional to the effective nuclear charge. |
The strong field nature of CN⁻ as a ligand can be attributed to:
1. It is a pseudohalide.
2. It can accept electrons from metal species.
3. It forms high-spin complexes with metal species.
4. It possesses a negative charge.
Considering H2O as a weak field ligand, the number of unpaired electrons in \([Mn(H_{2}O)_{6}]^{2+}\) will be:
(At. no. of Mn = 25)
| 1. | Five | 2. | Two |
| 3. | Four | 4. | Three |
The –OH group of an alcohol or the carboxylic acid can be replaced by – Cl using:
| 1. | Hypochlorous acid | 2. | Chlorine |
| 3. | Hydrochloric acid | 4. | Phosphorous pentachloride |
The reaction of HBr with propene in the presence of peroxide gives:
1. 2-bromopropane
2. Allyl bromide
3. n-propyl bromide
4. Isopropyl bromide
Chloropicrin is obtained by the reaction of:
1. Nitric acid on chlorobenzene.
2. Chlorine on picric acid.
3. Nitric acid on chloroform.
4. Steam on carbon tetrachloride.
Aniline when diazotized in cold and then treated with dimethyl aniline gives a coloured product. Its structure would be:
| 1. |  |
| 2. |  |
| 3. |  |
| 4. |  |
In a regular octahedral molecule, MX6, the number of X–M–X bonds at 180º is:
| 1. | 3 | 2. | 2 |
| 3. | 6 | 4. | 4 |
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