Three thermochemical equations are given below:
(i) C(graphite) + O2(g) \(\rightarrow\) CO2(g); \(\Delta_{r}\)H° = x kJ mol–1
(ii) Cgraphite + 1/2 O2(g) \(\rightarrow\) CO(g); \(\Delta_{r}\)H° = y kJ mol–1
(iii) CO(g) + 1/2 O2(g) \(\rightarrow\) CO2(g); \(\Delta_{r}\)H° = z kJ mol–1
Based on the above equations, find out which one of the relationships given below is correct :
1. z = x + y 2. x = y + z
3. y = 2z – x 4. x = y – z
Subtopic:  Hess's Law |
 79%
Level 2: 60%+
NEET - 2013
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What is the correct order of electron gain enthalpy from least negative to most negative for the elements C, Ca, Al, F, and O?
1. Al < Ca < O < C < F
2. Al < O < C < Ca < F
3. C < F < O < Al < Ca
4. Ca < Al < C < O < F
Subtopic:  Electron Affinity (EA) |
 82%
Level 1: 80%+
NEET - 2013
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The anion of acetylacetone (acac) forms Co(acac)3 chelate with Co3+. The rings of the chelate are:
1. Five membered
2. Four membered
3. Six membered
4. Three membered
Subtopic:  Ligands |
Level 3: 35%-60%
NEET - 2013
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At 100 °C the Kw of water is 55 times its value at 25ºC. What will be the pH of a neutral solution?
(log 55 = 1.74)
1. 7.00 2. 7.87
3. 5.13 4. 6.13
Subtopic:  pH calculation |
 57%
Level 3: 35%-60%
NEET - 2013
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Identify the incorrect statements, regarding the molecule XeO4:

1. XeO4 molecule is square planar
2. There are four p\(\pi\) – d\(\pi\) bonds
3. There are four sp3 – p, \(\sigma\) bonds
4. XeO4 molecule is tetrahedral
Subtopic:  V.S.E.P.R & V.B.T |
 65%
Level 2: 60%+
NEET - 2013
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In Castner-Kellner cell for the production of sodium hydroxide:
1. brine is electrolyzed using graphite electrodes
2. molten sodium chloride is electrolysed
3. sodium amalgam is formed at mercury cathode
4. brine is electrolyzed with Pt electrodes
Subtopic:  Compounds of Ca and Na -Preparations, Properties & Uses |
 59%
Level 3: 35%-60%
NEET - 2013
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Which of the following chemical system is non-aromatic?
1. 2.
3. 4.
Subtopic:  Aromaticity & Polarity |
 84%
Level 1: 80%+
NEET - 2013
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Phenol is distilled with Zn dust followed by Fridel Crafts alkylation with propyl chloride in the presence of AlCl3 to give a compound (B). (B) is oxidized in the presence of air to form the compound (C). The structural formula of (C) is:
 
1. 2.
3. 4.
Subtopic:  Phenols: Preparation & Properties |
 73%
Level 2: 60%+
NEET - 2013
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What is the formula of the blue-coloured compound formed during the detection of nitrogen by Lassaigne’s test?

1. Fe₃[Fe(CN)₆]₂

2. Fe₄[Fe(CN)₆]₃

3. Fe₄[Fe(CN)₆]₂

4. ​​​​​​​Fe₃[Fe(CN)₆]₃
Subtopic:  Qualitative Analysis of Organic Compounds |
 75%
Level 2: 60%+
NEET - 2013
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\(\mathrm{CH_3-CH_3, \ CH_3-CH_2-CH_3, \ }\)
\(\mathrm{\left(CH_3\right)_2 CH-CH_3, }\) and \(\mathrm{CH_3-CH_2-CH\left(CH_3\right)_2 }\)

The increasing order of stability of the free radicals formed from homolytic fission of the above three alkanes is:

1. \(\mathrm{ (CH_3)_2 \dot{C}-CH_2 CH_3<CH_3-\dot{C} H-CH_3 \\ <CH_3-\dot{C} H_2<(CH_3)_3 \dot{C} }\)
2. \( \mathrm{CH_3-\dot{C} H_2<CH_3-\dot{C} H-CH_3 \\ <\left(CH_3\right)_2 \dot{C}-CH_2 CH_3<\left(CH_3\right)_3 \dot{C}}\)
3. \(\mathrm{CH_3-\dot{C} H_2<CH_3-\dot{C} H-CH_3\\ <\left(CH_3\right)_3 \dot{C}<\left(CH_3\right)_2 \dot{C}-CH_2 CH_3 }\)
4. \(\mathrm{ \left(CH_3\right)_3 \dot{C}<\left(CH_3\right)_2 \dot{C}-CH_2-CH_3 \\ <CH_3-\dot{C} H-CH_3<CH_3-\dot{C} H_2 }\)
Subtopic:  Reaction Intermediates ; Preparation & Properties |
 79%
Level 2: 60%+
NEET - 2013
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