Crystal field splitting energy for high spin d4 octahedral complex is:
| 1. | – 1.2 \(\Delta_{0}\) | 2. | – 0.6 \(\Delta_{0}\) |
| 3. | – 0.8 \(\Delta_{0}\) | 4. | –1.6 \(\Delta_{0}\) |
Subtopic: VBT, CFT & their Limitations |
77%
Level 2: 60%+
NEET - 2013
Hints
Arrange the following in increasing order of stability:
| (a) | \(\left(\mathrm{CH}_3\right)_2 \stackrel{\oplus}{\mathrm{C}}-\mathrm{CH}_2-\mathrm{CH}_3 \) | (b) | \(\left(\mathrm{CH}_3\right)_3 \stackrel{\oplus}{\mathrm{C}} \) |
| (c) | \(\left(\mathrm{CH}_3\right)_2 \stackrel{\oplus}{\mathrm{C}}\mathrm{H} \) | (d) | \(\mathrm{CH}_3 \stackrel{\oplus}{\mathrm{C}}\mathrm{H}_2\) |
| (e) | \( \stackrel{\oplus}{\mathrm{C}}\mathrm{H}_3 \) | ||
| 1. | e < d < c < a < b | 2. | d < e < c < a < b |
| 3. | a < e < d < c < b | 4. | e < d < c < b < a |
Subtopic: Reaction Intermediates ; Preparation & Properties |
74%
Level 2: 60%+
NEET - 2013
Hints
Consider the half-cell reduction reaction:
\(\text{Mn}^{2+}+2e^-\rightarrow \text{Mn},\ E^{0}= -1.18~ \text V \)
\(\text{Mn}^{2+}\rightarrow \text{Mn}^{3+}+e^-,\ E^{0}= -1.51~ \text V \)
The \(E^{0}\) for the reaction \(\mathrm{3\ Mn^{2+}\rightarrow Mn^{0}+2Mn^{3+} }\) and possibility of the forward reaction are respectively:
\(\text{Mn}^{2+}+2e^-\rightarrow \text{Mn},\ E^{0}= -1.18~ \text V \)
\(\text{Mn}^{2+}\rightarrow \text{Mn}^{3+}+e^-,\ E^{0}= -1.51~ \text V \)
The \(E^{0}\) for the reaction \(\mathrm{3\ Mn^{2+}\rightarrow Mn^{0}+2Mn^{3+} }\) and possibility of the forward reaction are respectively:
| 1. | –4.18 V and Yes | 2. | +0.33 V and Yes |
| 3. | +2.69 V and No | 4. | –2.69 V and No |
Subtopic: Electrode & Electrode Potential |
56%
Level 3: 35%-60%
NEET - 2013
Hints
How many grams of cobalt metal will be deposited when a solution of cobalt (II) chloride is electrolyzed with a current of 10 amperes for 109 minutes?
(Given: 1 Faraday = 96,500 C; Atomic mass of Co = 59 u)
(Given: 1 Faraday = 96,500 C; Atomic mass of Co = 59 u)
| 1. | 4.0 | 2. | 20.0 |
| 3. | 40.0 | 4. | 0.66 |
Subtopic: Faraday’s Law of Electrolysis |
71%
Level 2: 60%+
NEET - 2013
Hints
In a particular isomer of [Co(NH3)4Cl2]°, the Cl–Co–Cl angle is 90°, and the isomer is known as:
| 1. | Optical isomer | 2. | Cis-isomer |
| 3. | Position isomer | 4. | Linkage isomer |
Subtopic: Isomerism in Coordination Compounds |
75%
Level 2: 60%+
NEET - 2013
Hints
Which one of the following statements is not true?
| 1. | Clean water would have a BOD value of 5 ppm. |
| 2. | Fluoride deficiency in drinking water is harmful. Soluble fluoride is often used to bring its concentration upto 1 ppm. |
| 3. | When the pH of rainwater is higher than 6.5, it is called acid rain. |
| 4. | Dissolved Oxygen (DO) in cold water can reach a concentration upto 10 ppm. |
Subtopic: Air Pollution - Acid Rain | Water Pollution - Water Pollution & Portable Water |
69%
Level 2: 60%+
NEET - 2013
Hints
Calculate the heat released when 5 L of a gaseous mixture of methane (CH₄) and propane (C₃H₈) is completely combusted at 0°C and 1 atm, given that 16 L of oxygen is consumed.
Enthalpy of combustion: ΔHc(CH₄) = 890 kJ mol⁻¹, ΔHc(C₃H₈) = 2220 kJ mol⁻¹.
Enthalpy of combustion: ΔHc(CH₄) = 890 kJ mol⁻¹, ΔHc(C₃H₈) = 2220 kJ mol⁻¹.
| 1. | 38 | 2. | 317 |
| 3. | 477 | 4. | 32 |
Subtopic: Thermochemistry |
64%
Level 2: 60%+
NEET - 2013
Hints
is:
Subtopic: Hybridisation & Structure of Carbon Compounds |
84%
Level 1: 80%+
NEET - 2013
Hints
The pair of species that has the same bond order in the following is:
| 1. | CO, NO+ | 2. | NO–, CN– |
| 3. | O2, N2 | 4. | O2, B2 |
Subtopic: M.O.T |
84%
Level 1: 80%+
NEET - 2013
Hints
Find the energy absorbed per mole of photons according to the law of photochemical equivalence using:
E = Nₐhc/λ
Given:
h = 6.62 × 10⁻²⁷ erg s
c = 3 × 10¹⁰ cm s⁻¹
Nₐ = 6.02 × 10²³ mol⁻¹
| 1. | \({{1.196\times 10^{8}}\over{\lambda}}\) | 2. | \({{2.859\times 10^{5}}\over{\lambda}}\) |
| 3. | \({{2.859\times 10^{16}}\over{\lambda}}\) | 4. | \({{1.196\times 10^{16}}\over{\lambda}}\) |
Subtopic: Electromagnetic Radiation |
63%
Level 2: 60%+
NEET - 2013
Hints
© 2026 GoodEd Technologies Pvt. Ltd.