The two-dimensional motion of a particle, described by \(\vec{r}=(\hat{i}+2\hat{j}) A~\text{cos}(\omega t) \) is a/an:
Choose the correct answer from the options given below:
| (A) | parabolic path |
| (B) | elliptical path |
| (C) | periodic motion |
| (D) | simple harmonic motion |
Choose the correct answer from the options given below:
| 1. | (B), (C), and (D) only |
| 2. | (A), (B), and (C) only |
| 3. | (A), (C), and (D) only |
| 4. | (C) and (D) only |
Subtopic: Types of Motion |
52%
Level 3: 35%-60%
NEET - 2024
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A beam of unpolarised light of intensity \(I_0\) is passed through a polaroid \(A,\) through another polaroid \(B,\) oriented at \(60^\circ\) and finally through another polaroid \(C,\) oriented at \(45^\circ\) relative to \(B\) as shown in the figure. The intensity of the emergent light is:
| 1. | \(\dfrac{{I}_0}{16}\) | 2. | \(\dfrac{{I}_0}4\) |
| 3. | \(\dfrac{{I}_0}2\) | 4. | \(\dfrac{{I}_0}{32}\) |
Subtopic: Polarization of Light |
78%
Level 2: 60%+
NEET - 2024
Hints
Select the correct statements among the following:
Choose the most appropriate answer from the options given below:
| A. | slow neutrons can cause fission in \(\mathrm U_{92}^{235}\) than fast neutrons. |
| B. | \(\text{α-rays}\) are helium nuclei. |
| C. | \(\text{β-rays}\) are fast-moving electrons or positrons. |
| D. | \(\gamma\text-\text{rays}\) are electromagnetic radiations of wavelengths larger than \(X\text-\)rays. |
| 1. | A, B, and C only | 2. | A, B, and D only |
| 3. | A and B only | 4. | C and D only |
Subtopic: Nuclear Energy |
68%
Level 2: 60%+
NEET - 2024
Hints
Let \(\omega_{1},\omega_{2}\) and \(\omega_{3}\) be the angular speeds of the second hand, minute hand, and hour hand of a smoothly running analog clock, respectively. If \(x_{1},x_{2}\) and \(x_{3}\) are their respective angular distance in \(1~\text{minute},\) then the factor that remains constant \((k)\) is:
| 1. | \(\dfrac{\omega_1}{x_1}=\dfrac{\omega_2}{x_2}=\dfrac{\omega_3}{x_3}={k}\) |
| 2. | \(\omega_{1}x_{1}=\omega_{2}x_{2}=\omega_{3}x_{3}={k}\) |
| 3. | \(\omega_{1}x_{1}^{2}=\omega_{2}x_{2}^{2}=\omega_{3}x_{3}^{2}={k}\) |
| 4. | \(\omega_{1}^{2}x_{1}=\omega_{2}^{2}x_{2}=\omega_{3}^{2}x_{3}={k}\) |
Subtopic: Rotational Motion: Kinematics |
55%
Level 3: 35%-60%
NEET - 2024
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The magnetic moment of an iron bar is \(M.\) It is now bent in such a way that it forms an arc section of a circle subtending an angle of \(60^\circ\) at the centre. The magnetic moment of this arc section is:
| 1. | \(\dfrac{3 M}{\pi}\) | 2. | \(\dfrac{4M}{\pi}\) |
| 3. | \(\dfrac{ M}{\pi}\) | 4. | \(\dfrac{2 M}{\pi}\) |
Subtopic: Bar Magnet |
77%
Level 2: 60%+
NEET - 2024
Hints
The given circuit shows a uniform straight wire \(AB\) of \(40 ~\text{cm}\) length fixed at both ends. In order to get zero reading in the galvanometer \(G,\) the free end of \(J\) is to be placed from the end \(B\) at:
| 1. | \(32~\text{cm}\) | 2. | \(8~\text{cm}\) |
| 3. | \(16~\text{cm}\) | 4. | \(24~\text{cm}\) |
Subtopic: Wheatstone Bridge |
67%
Level 2: 60%+
NEET - 2024
Hints
According to the law of equipartition of energy, the number of vibrational modes of a polyatomic gas of constant \(\gamma=\dfrac{C_{\mathrm{p}}}{C_{\mathrm{v}}}\) is (where \(C_p\) and \(C_v\) are the specific heat capacities of the gas at constant pressure and constant volume, respectively):
| 1. | \(\dfrac{4+3\gamma}{\gamma-1}\) | 2. | \(\dfrac{3+4\gamma}{\gamma-1}\) |
| 3. | \(\dfrac{4-3\gamma}{\gamma-1}\) | 4. | \(\dfrac{3-4\gamma}{\gamma-1}\) |
Subtopic: Law of Equipartition of Energy |
Level 3: 35%-60%
NEET - 2024
Hints
The output \(Y\) for the inputs \(A\) and \(B\) of the given logic circuit is:
| 1. | \(A\cdot B\) | 2. | \(\overline{A}\cdot\overline{B}\) |
| 3. | \(A+B\) | 4. | \(\overline{A}+\overline{B}\) |
Subtopic: Logic gates |
70%
Level 2: 60%+
NEET - 2024
Hints
The amplitude of the charge oscillating in a circuit decreases exponentially as \(\mathrm{Q=Q_{0}e}^{-Rt/2L}\) where \({Q}_0\) is the charge at \({t}=0~\text{s}.\)The time at which charge amplitude decreases to \(0.50~{Q}_0\) is nearly:
\((\text{Given that}~ {R=1.5~\Omega,~L=12~\text{mH},~\text{ln}(2)=0.693})\)
1. \(19.01~\text{ms}\)
2. \(11.09~\text{ms}\)
3. \(19.01~\text s\)
4. \(11.09~\text s\)
\((\text{Given that}~ {R=1.5~\Omega,~L=12~\text{mH},~\text{ln}(2)=0.693})\)
1. \(19.01~\text{ms}\)
2. \(11.09~\text{ms}\)
3. \(19.01~\text s\)
4. \(11.09~\text s\)
67%
Level 2: 60%+
NEET - 2024
Hints
The steady-state current in the circuit shown below is:
| 1. | \(0.67~\text A\) | 2. | \(1.5~\text A\) |
| 3. | \(2~\text A\) | 4. | \(1~\text A\) |
Subtopic: Derivation of Ohm's Law |
72%
Level 2: 60%+
NEET - 2024
Hints
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