1.00 g of non-electrolyte solute (molar mass 250 g mol-1) was dissolved in 51.2 g of benzene. If the freezing point depression constant, Kf of benzene is 5.12 mol-1 kg K, the freezing point of benzene will be lowered by:

1. 0.4 K

2. 0.3 K

3. 0.5 K

4. 0.2 K

Subtopic:  Elevation of Boiling Point |
 84%
Level 1: 80%+
AIPMT - 2006
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Find the pair that constitutes a buffer solution.

1. HNO₂ and NaNO₂
2. NaOH and NaCl
3. HNO₃ and NH₄NO₃
4. HCl and KCl
Subtopic:  Buffer |
 66%
Level 2: 60%+
AIPMT - 2006
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The hydrogen ion concentration of a 10-8 M HCl aqueous solution at 298 K (Kw = 10-14) is:

1. \(1 . 0 \times \left(10\right)^{- 6}\) \(M\)

2. \(1 . 0525 \times \left(10\right)^{- 7}\) \(M\)

3. \(9 . 525 \times \left(10\right)^{- 8}\) \(M\)

4. \(1 . 0 \times \left(10\right)^{- 8}\) \(M\)

Subtopic:  pH calculation |
 54%
Level 3: 35%-60%
AIPMT - 2006
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A solution of acetone in ethanol:

1. Shows a negative deviation from Raoult's law
2. Shows a positive deviation from Raoult's law
3. Behaves like a near-ideal solution
4. Obeys Raoult's law
Subtopic:  Raoult's Law |
 78%
Level 2: 60%+
AIPMT - 2006
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For the hypothetical electrochemical cell given below:

A | A⁺(x M) || B⁺(y M) | B .

The measured cell emf is +0.20 V. Find the overall cell reaction.

1. A+ + B → A + B+

2.  A+ + e- → A ; B+ + e- → B

3. The cell reaction cannot be predicted.

4. A + B+ → A+ + B

Subtopic:  Electrochemical Series | Nernst Equation |
 77%
Level 2: 60%+
AIPMT - 2006
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Ethylene oxide when treated with Grignard reagent yields:

1. secondary alcohol

2. tertiary alcohol

3. cyclopropyl alcohol

4. primary alcohol

Subtopic:  Alcohols: Preparation & Properties | Ethers: Preparation & Properties, Uses |
Level 3: 35%-60%
AIPMT - 2006
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During osmosis, the flow of water through a semi-permeable membrane is:

1. From a solution having higher concentration only. 
2. From both sides of the semi-permeable membrane with equal flow rates.
3. From both sides of the semi-permeable membrane with unequal flow rates.
4. From a solution having lower concentration only.
Subtopic:  Osmosis & Osmotic Pressure |
Level 3: 35%-60%
AIPMT - 2006
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Which of the following compounds has a higher basic character than aniline?

1. Diphenylamine

2. Triphenylamine

3. p-nitroaniline

4. Benzylamine

Subtopic:  Amines - Preparation & Properties |
 71%
Level 2: 60%+
AIPMT - 2006
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Find the molecule in which not all the bonds are equal.

1. ClF3 2. BF3
3. AlF3 4. NF3
Subtopic:  Hybridisation |
 68%
Level 2: 60%+
AIPMT - 2006
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The electronegativity difference between N and F is greater than that between N and H yet the dipole moment of NH3 (1.5 D) is larger than that of NF3 (0.2 D). This is because:

1. In NH3 as well as in NF3 the atomic dipole and bond dipole are in the same direction
2. In NH3  the atomic dipole and bond dipole are in the same direction whereas in NF3 these are in opposite directions
3. In NH3 as well as in NF3 the atomic dipole and bond dipole are in opposite directions
4. In NH3  the atomic dipole and the bond dipole is in opposite directions whereas in NF3 these are in the same directions

Subtopic:  Group 15 - Preparation, Properties & Uses |
 80%
Level 1: 80%+
AIPMT - 2006
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