A reaction having equal energies of activation for forward and reverse reaction has:

1. ΔG = 0

2. ΔH = 0

3. ΔH = ΔG = ΔS = 0

4. ΔS = 0

The cell potential will be:

Nitrobenzene on reaction with conc. HNO₃ /H₂SO₄ at 80 – 100 ºC forms:

1. 1,3– Dinitrobenzene

2. 1,4–Dinitrobenzene

3. 1,2,4–Trinitrobenzene

4. 1,2–Dinitrobenzene

A uniform force of \((3 \hat{i} + \hat{j})\) newton acts on a particle of mass \(2~\text{kg}.\) Hence the particle is displaced from the position \((2 \hat{i} + \hat{k})\) metre to the position \((4 \hat{i} + 3 \hat{j} - \hat{k})\) metre. The work done by the force on the particle is:
1. \(6~\text{J}\)
2. \(13~\text{J}\)
3. \(15~\text{J}\)
4. \(9~\text{J}\)

\(A\), \(B\) and \(C\) are three points in a uniform electric field. The electric potential is: 

     

1.	maximum at \(B\)
2.	maximum at \(C\)
3.	same at all the three points \(A, B\) and \(C\)
4.	maximum at \(A\)

The upper half of an inclined plane of inclination \(\theta\) is perfectly smooth while the lower half is rough. A block starting from rest at the top of the plane will again come to rest at the bottom if the coefficient of friction between the block and the lower half of the plane is given by:
1. \(\mu=2/\tan \theta\)
2. \(\mu=2\tan \theta\)
3. \(\mu=\tan \theta\)
4. \(\mu=1/\tan \theta\)