To ensure that only the desired pollens fall on the stigma in artificial hybridization process:
Choose the correct answer from the options given below:
| a: | the female flower buds of plant producing unisexual flower need not be bagged. |
| b: | there is no need to emasculate unisexual flowers of selected female parent. |
| c: | emasculated flowers are to be bagged immediately after cross pollination. |
| d: | emasculated flowers are to be bagged after removal of anthers. |
| e: | bisexual flowers, showing protogyny are never selected for cross. |
| 1. | (a), (b) and (c) only | 2. | (b), (c) and (d) only |
| 3. | (b), (c) and (e) only | 4. | (a), (d) and (e) only |
Subtopic: Pollen - Pistil Interaction |
67%
Level 2: 60%+
NEET - 2022
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The residual persistent part which forms the perisperm in the seeds of beet is :
1. Calyx
2. Endosperm
3. Nucellus
4. Integument
1. Calyx
2. Endosperm
3. Nucellus
4. Integument
Subtopic: Embryo | Seed |
79%
Level 2: 60%+
NEET - 2022
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The chromosomal theory of inheritance was proposed by:
1. Thomas Morgan
2. Sutton and Boveri
3. Gregor Mendel
4. Robert Brown
1. Thomas Morgan
2. Sutton and Boveri
3. Gregor Mendel
4. Robert Brown
Subtopic: Chromosomal Basis of Inheritance: Introduction |
84%
Level 1: 80%+
NEET - 2022
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Which of the following protects nitrogenase inside the root nodule of a leguminous plant ?
1. Catalase
2. leg haemoglobin
3. Transaminase
4. Glutamate dehydrogenase
1. Catalase
2. leg haemoglobin
3. Transaminase
4. Glutamate dehydrogenase
Subtopic: Nitrogen Fixation | Nodule formation |
87%
Level 1: 80%+
NEET - 2022
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The ability of plants to follow different pathways in response to environment leading to formation of different kinds of structures are called :
1. Redifferentiation
2. Development
3. Plasticity
4. Differentiation
1. Redifferentiation
2. Development
3. Plasticity
4. Differentiation
Subtopic: Development |
92%
Level 1: 80%+
NEET - 2022
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Which of the following pair represents free living nitrogen fixing aerobic bacteria?
1. Rhizobium and Frankia
2. Azotobacter and Beijernickia
3. Anabaena and Rhodospirillum
4. Pseudomonas and Thiobacillus
1. Rhizobium and Frankia
2. Azotobacter and Beijernickia
3. Anabaena and Rhodospirillum
4. Pseudomonas and Thiobacillus
Subtopic: Nitrogen Fixation | Nodule formation |
69%
Level 2: 60%+
NEET - 2022
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Match List-I with List-II:
Choose the correct answer from the options given below:
| List-I | List-II | ||
| (a) | Sacred groves | (i) | Alien species |
| (b) | Zoological park | (ii) | Release of large quantity of oxygen |
| (c) | Nile perch | (iii) | Ex-situ conservation |
| (d) | Amazon forest | (iv) | Khasi Hills in Meghalaya |
| (a) | (b) | (c) | (d) | |
| 1. | (iv) | (iii) | (i) | (ii) |
| 2. | (ii) | (iv) | (i) | (iii) |
| 3. | (iv) | (i) | (ii) | (iii) |
| 4. | (iv) | (iii) | (ii) | (i) |
Subtopic: Miscellaneous |
93%
Level 1: 80%+
NEET - 2022
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Primary proteins are also known as polypeptides, because:
1. they are linear chains.
2. they are polymers of peptide monomers.
3. successive amino acids are joined by peptide bonds.
4. they can assume many conformations.
1. they are linear chains.
2. they are polymers of peptide monomers.
3. successive amino acids are joined by peptide bonds.
4. they can assume many conformations.
Subtopic: Proteins |
56%
Level 3: 35%-60%
NEET - 2022
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Match List-I with List-II:
Choose the correct answer from the options given below:
| List-I | List-II | ||
| (a) | Gene gun | (i) | Replacement of a faulty gene by a normal healthy gene |
| (b) | Gene therapy | (ii) | Used for transfer of gene |
| (c) | Gene cloning | (iii) | Total DNA in the cells of an organism |
| (d) | Genome | (iv) | To obtain identical copies of a particular DNA molecule |
Choose the correct answer from the options given below:
| (a) | (b) | (c) | (d) | |
| 1. | (ii) | (i) | (iv) | (iii) |
| 2. | (i) | (iii) | (ii) | (iv) |
| 3. | (iv) | (i) | (iii) | (ii) |
| 4. | (ii) | (iii) | (iv) | (i) |
Subtopic: Transforming Plant & Animal Cell |
92%
Level 1: 80%+
NEET - 2022
Hints
Match List-I with List-II
Choose the correct answer from the options given below:
| List-I | List-II | ||
| (a) | Bacteriophage \(\phi \times 174\) | (i) | 48502 base pairs |
| (b) | Bacteriophage lambda | (ii) | 5386 nucleotides |
| (c) | Escherichia coli | (iii) | 3.3 × 109 base pairs |
| (d) | Haploid content human DNA | (iv) | 4.6 × 106 base pairs |
Choose the correct answer from the options given below:
| (a) | (b) | (c) | (d) | |
| 1. | (i) | (ii) | (iii) | (iv) |
| 2. | (ii) | (iv) | (i) | (iii) |
| 3. | (ii) | (i) | (iv) | (iii) |
| 4. | (i) | (ii) | (iv) | (iii) |
Subtopic: The DNA |
84%
Level 1: 80%+
NEET - 2022
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