Oxidation numbers of P in PO43-, of S in SO42- and that of Cr in Cr2O72-are respectively:
1. +5, +6 and +6
2. +3, +6 and +5
3. +5, +3 and +6
4. -3, +6 and +6

Subtopic:  Oxidizing & Reducing Agents |
 91%
Level 1: 80%+
AIPMT - 2009
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The IUPAC name of the compound having the formula CH≡C–CH=CH2 is:

1. 3-butene-1-yne

2. 1-butyn-3-ene

3. but-1-yne-3-ene

4. 1-butene-3-yne

Subtopic:  Nomenclature |
 73%
Level 2: 60%+
AIPMT - 2009
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In the case of alkali metals, the covalent character decreases in the order:

1. MCl>Ml>MBr>MF

2. MF>MCl>MBr>Ml

3. MF>MCl>Ml>MBr

4. Ml>MBr>MCl>MF

Subtopic:  Chemical Properties |
 62%
Level 2: 60%+
AIPMT - 2009
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Given:
(i) Cu2++2e-→Cu    Eo = 0.337 V 
(ii) Cu2++e-→Cu+  Eo = 0.153 V 
Electrode potential, Eo for the reaction, 
Cu++e-→Cu, will be: 

1. 0.52 V

2. 0.90 V

3. 0.30 V

4. 0.38 V

Subtopic:  Relation between Emf, G, Kc & pH |
 76%
Level 2: 60%+
AIPMT - 2009
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For the reaction, \(\mathrm{N}_2+3 \mathrm{H}_2 \rightarrow 2 \mathrm{NH}_3,\) if, \(\dfrac{d[NH_{3}]}{dt} \ = \ 2\times 10^{-4} \ mol \ L^{-1} \ s^{-1}\), the value of  \(\dfrac{-d[H_{2}]}{dt}\) would be:
1. \(3 \times 10^{-4} \mathrm{~mol} \mathrm{~L}^{-1} \mathrm{~s}^{-1} \)
2. \(4 \times 10^{-4} \mathrm{~mol} \mathrm{~L}^{-1} \mathrm{~s}^{-1} \)
3. \(6 \times 10^{-4} \mathrm{~mol} \mathrm{~L}^{-1} \mathrm{~s}^{-1} \)
4. \(1 \times 10^{-4} \mathrm{~mol} \mathrm{~L}^{-1} \mathrm{~s}^{-1}\)
Subtopic:  Definition, Rate Constant, Rate Law |
 86%
Level 1: 80%+
AIPMT - 2009
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What is the [OH-] in the final solution prepared by mixing 20.0 mL of 0.050 M HCl with 30.0 mL of 0.10 M Ba(OH)2?

1. 0.10 M

2. 0.40 M

3. 0.0050 M

4. 0.12 M

Subtopic:  pH calculation |
 65%
Level 2: 60%+
AIPMT - 2009
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Which of the following pairs consists of colourless species?

(Given: Atomic numbers of Ti = 22, Co = 27, Cu = 29 and Ni = 28)

1.[TiF₆]²⁻ and [CoF₆]³⁻
2. Cu₂Cl₂ and [NiCl₄]²⁻
3. [TiF₆]²⁻ and Cu₂Cl₂
4. [CoF₆]³⁻ and [NiCl₄]²⁻

Subtopic:  Introduction, Classification and Nomenclature |
 78%
Level 2: 60%+
AIPMT - 2009
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Amongst the elements with the following electronic configurations, which one of them may have the highest ionisation energy?

1. [Ne] 3s2 3p2

2. [Ne] 3s2 3p3

3. [Ar] 3d10 4s2 4p3

4. [Ne] 3s2 3p1

Subtopic:  Ionization Energy (IE) | Electronic Configuration |
Level 4: Below 35%
AIPMT - 2009
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The rule used to determine the maximum number of electrons in a subshell of an atom is:

1. 4l+2 2. 2l+1
3. 4l-2 4. 2n2
Subtopic:  Shell & Subshell |
 69%
Level 2: 60%+
AIPMT - 2009
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Lithium metal crystallizes in a body-centered cubic crystal. If the length of the side of the unit cell of lithium is 351 pm, the atomic radius of the lithium will be:

1. 240.8 pm

2. 151.8 pm

3. 75.5 pm

4. 300.5 pm

Subtopic:  Introduction & Crystal System |
 83%
Level 1: 80%+
AIPMT - 2009
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