Which of the following compounds produces methyl alcohol on treatment with hot concentrated HI?
| 1. |  |
| 2. |  |
| 3. |  |
| 4. |  |
Subtopic: Mechanism of Dehydration, Methanol & Ethanol |
83%
Level 1: 80%+
AIPMT - 2013
Hints
Which of the following is not a monomer for a high molecular mass silicone polymer?
| 1. | Me2SiCl2 | 2. | Me3SiCl |
| 3. | PhSiCl3 | 4. | MeSiCl3 |
Subtopic: Properties of Structure of SiO2 & Other Compounds |
56%
Level 3: 35%-60%
AIPMT - 2013
Hints
Identify the correct order of solubility in aqueous medium:
1. ZnS > Na2S > CuS
2. Na2S > CuS > ZnS
3. Na2S > ZnS > Cus
4. Cus > ZnS > Na2S
2. Na2S > CuS > ZnS
3. Na2S > ZnS > Cus
4. Cus > ZnS > Na2S
Subtopic: d-Block Elements- Properties & Uses |
Level 3: 35%-60%
AIPMT - 2013
Hints
What is the activation energy for a reaction if its rate doubles when the temperature is raised from 20oC to 35oC? (R = 8.314 J mol–1 K–1)
| 1. | 269 kJ mol–1 | 2. | 34.7 kJ mol–1 |
| 3. | 15.1 kJ mol–1 | 4. | 342 kJ mol–1 |
Subtopic: Arrhenius Equation |
68%
Level 2: 60%+
AIPMT - 2013
Hints
A hydrogen gas electrode is made by dipping platinum wire in a solution of HCl of pH = 10 and by passing hydrogen gas around the platinum wire at one atm pressure. The oxidation potential of the electrode would be:
| 1. | 0.59 V | 2. | 0.118 V |
| 3. | 1.18 V | 4. | 0.059 V |
Subtopic: Relation between Emf, G, Kc & pH |
78%
Level 2: 60%+
AIPMT - 2013
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Links
The value of Planck's constant is 6.63 × 10–34 Js. The speed of light is 3 × 1017 nm s–1. Which value is closest to the wavelength in nanometers of a quantum of light with a frequency of 6 × 1015 s–1?
1. 25
2. 50
3. 75
4. 10
1. 25
2. 50
3. 75
4. 10
Subtopic: Electromagnetic Radiation |
86%
Level 1: 80%+
AIPMT - 2013
Hints
What is the maximum number of electrons that can be associated with the following set of quantum numbers?
n = 3, l = 1 and m = –1.
n = 3, l = 1 and m = –1.
| 1. | 6 | 2. | 4 |
| 3. | 2 | 4. | 10 |
Subtopic: Quantum Numbers & Schrodinger Wave Equation |
76%
Level 2: 60%+
AIPMT - 2013
Hints
Diamagnetic lanthanoid ion among the following is:
(At nos. Ce = 58, Sm = 62, Eu = 63, Yb = 70)
1. Sm2+
2. Eu2+
3. Yb2+
4. Ce2+
(At nos. Ce = 58, Sm = 62, Eu = 63, Yb = 70)
1. Sm2+
2. Eu2+
3. Yb2+
4. Ce2+
Subtopic: f-Block Elements- Properties & Uses |
67%
Level 2: 60%+
AIPMT - 2013
Hints
6.02 × 1020 molecules of urea are present in 100 mL of its solution. The concentration of the solution is:
| 1. | 0.01 M | 2. | 0.001 M |
| 3. | 0.1 M | 4. | 0.02 M |
Subtopic: Concentration Based Problem |
79%
Level 2: 60%+
AIPMT - 2013
Hints
Based on equation E = –2.178 × 10–18J, certain conclusions are written. Which of them is not correct?
| 1. | The larger the value of n, the larger the orbit radius. |
| 2. | An equation can be used to calculate the change in energy when the electron changes orbit. |
| 3. | For n = 1, the electron has a more negative energy than it does for n = 6 which means that the electron is more loosely bound in the smallest allowed orbit. |
| 4. | The negative sign in the equation simply means that the energy of the electron bound to the nucleus is lower than what it would be if the electrons were at an infinite distance from the nucleus. |
Subtopic: Bohr's Theory |
67%
Level 2: 60%+
AIPMT - 2013
Hints
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