- 1(current)
Q. No.At 100 °C the vapour pressure of a solution of 6.5 g of a solute in 100 g water is 732 mm. If Kb = 0.52, the boiling point of this solution will be:
| 1. | 100 oC | 2. | 102 oC |
| 3. | 103 oC | 4. | 101 oC |
Subtopic: Relative Lowering of Vapour Pressure | Elevation of Boiling Point |
59%
Level 3: 35%-60%
NEET - 2016
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The boiling point of 0.2 mol kg–1 solution of X in water is greater than the equimolal solution of Y in water. The correct statement in this case is:
| 1. | X is undergoing dissociation in water. |
| 2. | Molecular mass of X is greater than the molecular mass of Y. |
| 3. | Molecular mass of X is less than the molecular mass of Y. |
| 4. | Y is undergoing dissociation in water while X undergoes no change. |
Subtopic: Elevation of Boiling Point |
60%
Level 2: 60%+
NEET - 2015
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- 1(current)
Q. No.
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