+91-8527521718
Signup | Login
  • 1(current)
Q. No.

The arrangement in decreasing order of stability of C∙H3, C2∙H5,(CH3)2C∙H and (CH3)3 C∙ free radicals is:

1. C∙H3 > C2∙H5 > (CH3)2C∙H > (CH3)3 C∙  

2. (CH3)3 C∙ > (CH3)2C∙H > C2∙H5 > C∙H3

3. C2∙H5 > C∙H3 > (CH3)2C∙H > (CH3)3 C∙

4. (CH3)3 C∙ > (CH3)2C∙H >  C∙H3  > C2∙H5 

Subtopic:  Reaction Intermediates ; Preparation & Properties |
 86%
Level 1: 80%+
Hints
Links

The most stable carbocation among the following is:

1. 2.
3. 4.
Subtopic:  Reaction Intermediates ; Preparation & Properties |
 78%
Level 2: 60%+
Hints
Links
  • 1(current)
Q. No.
NEET Information
courses
Company
Compare NEETprep
Botany Questions
Chemistry Questions
Physics Questions
Zoology Questions

© 2026 GoodEd Technologies Pvt. Ltd.