Boron has two isotopes B105 and B115. If atomic weight of Boron is 10.81 then ratio of B105 to B115in nature will be: 

1. 15 : 16 

2. 19: 81

3. 81 : 19 

4. 20: 53

Subtopic:  Mass-Energy Equivalent |
 67%
From NCERT
AIPMT - 1998
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For the nuclear reaction:
\({}_{92}^{235}\mathrm{U}+ {}_{0}^{1}\mathrm{n}\rightarrow {}_{56}^{144}\mathrm{Ba}+...+3{}_{0}^{1}\mathrm{n}\)
The blank space can be filled by:
1. \({}_{26}^{89}\mathrm{Kr}\)
2. \({}_{36}^{89}\mathrm{Kr}\)
3. \({}_{26}^{90}\mathrm{Sr}\)
4. \({}_{38}^{89}\mathrm{Sr}\)

Subtopic:  Nuclear Energy |
 87%
From NCERT
AIPMT - 1998
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Xmn emitted one αandβ particles, then it will become: 

1. Xm-4n

2. Xm-1n-1

3. Zm-4n

4. None of these

Subtopic:  Types of Decay |
 68%
From NCERT
AIPMT - 1998
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When \(\mathrm{X}\rightarrow {}_{7}^{14}\mathrm{N}+2\beta^{-}\) then the number of neutrons in \(\mathrm{X}\) will be:
1. \(3\)
2. \(5\)
3. \(7\)
4. \(9\)

Subtopic:  Types of Decay |
 58%
From NCERT
AIPMT - 1998
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If a radioactive element emitted one \(\alpha\) and one \(\beta\text-\)particle, then the mass number of the daughter element is:
1. decreased by \(4\)
2. increased by \(4\)
3. decreased by \(2\)
4. increased by \(2\)

Subtopic:  Types of Decay |
 86%
From NCERT
AIPMT - 1999
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For the given reaction, the particle \(\mathrm{X}\) is:
\({ }_6^{11} \mathrm{C}\rightarrow { }_5^{11}\mathrm{B}+\beta^{+}+\mathrm{X}\)
1. neutron
2. anti-neutrino
3. neutrino
4. proton

Subtopic:  Types of Decay |
 65%
From NCERT
AIPMT - 2000
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Nuclear–fission is best explained by:
1. Liquid droplet theory.
2. Yukawa \(\pi\text-\)meson theory.
3. Independent particle model of the nucleus.
4. Proton-proton cycle.
Subtopic:  Nuclear Energy |
From NCERT
AIPMT - 2000
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Which rays contain (+ve) charged particle:
1.  α-rays
2.  β-rays
3.  γ-rays
4.  X-rays

Subtopic:  Types of Decay |
 71%
From NCERT
AIPMT - 2001
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If X(n, α ) converts into  L37i, then X will be: 

1. B510

2.  B59

3. B411e

4. H24e

Subtopic:  Types of Decay |
 57%
From NCERT
AIPMT - 2001
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\(M_n~\text{and}~M_p\) represent the mass of the neutron and proton respectively. An element having mass \(M\) has \(N\) neutrons and \(Z\)-protons, then the correct relation will be:
1. \(M <\left \{N.M_n+Z.M_p \right \}\)
2. \(M >\left \{N.M_n+Z.M_p \right \}\)
3. \(M =\left \{N.M_n+Z.M_p \right \}\)
4. \(M =N\left \{M_n+M_p \right \}\)

Subtopic:  Nuclear Binding Energy |
 80%
From NCERT
AIPMT - 2001
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