- 1(current)
Q. No.
1. \(2.5\)
2. \(8\)
3. \(7\)
4. \(5\)
1. \(2:1\)
2. \(4:1\)
3. \(1:4\)
4. \(1:2\)
| 1. | \(M=m\) | 2. | \(M=2m\) |
| 3. | \(M\ll m\) | 4. | \(M\gg m\) |
| 1. | \(3 \sqrt{2} v\) | 2. | \(v\) |
| 3. | \(\sqrt{2} v\) | 4. | \(2 \sqrt{2} v\) |
| 1. | \(3:1\) | 2. | \(1:4\) |
| 3. | \(1:1\) | 4. | \(1:3\) |
| Assertion (A): | When a firecracker (rocket) explodes in mid-air, its fragments fly in such a way that they continue moving in the same path, which the firecracker would have followed, had it not exploded. |
| Reason (R): | The explosion of cracker (rocket) occurs due to internal forces only and no external force acts for this explosion. |
| 1. | Both (A) and (R) are True and (R) is the correct explanation of (A). |
| 2. | Both (A) and (R) are True but (R) is not the correct explanation of (A). |
| 3. | (A) is True but (R) is False. |
| 4. | (A) is False but (R) is True. |
Body \(\mathrm{A}\) of mass \(4m\) moving with speed \(u\) collides with another body \(\mathrm{B}\) of mass \(2m\) at rest. The collision is head-on and elastic in nature. After the collision, the fraction of energy lost by the colliding body \(\mathrm{A}\) is:
| 1. | \(\dfrac{5}{9}\) | 2. | \(\dfrac{1}{9}\) |
| 3. | \(\dfrac{8}{9}\) | 4. | \(\dfrac{4}{9}\) |
An object flying in the air with velocity \((20 \hat{i}+25 \hat{j}-12 \hat{k})\) suddenly breaks into two pieces whose masses are in the ratio of \(1:5.\) The smaller mass flies off with a velocity \((100 \hat{i}+35 \hat{j}+8 \hat{k})\). The velocity of the larger piece will be:
1. \( 4 \hat{i}+23 \hat{j}-16 \hat{k}\)
2. \( -100 \hat{i}-35 \hat{j}-8 \hat{k} \)
3. \( 20 \hat{i}+15 \hat{j}-80 \hat{k} \)
4. \( -20 \hat{i}-15 \hat{j}-80 \hat{k}\)
A particle of mass \(5m\) at rest suddenly breaks on its own into three fragments. Two fragments of mass \(m\) each move along mutually perpendicular directions with speed \(v\) each. The energy released during the process is:
| 1. | \(\dfrac{3}{5}mv^2\) | 2. | \(\dfrac{5}{3}mv^2\) |
| 3. | \(\dfrac{3}{2}mv^2\) | 4. | \(\dfrac{4}{3}mv^2\) |
- 1(current)
Q. No.
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