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Q. No.
For the pedigree given above which shows the inheritance of an autosomal recessive disorder, what is the genotype of the individual II - 3 ?
| 1. | AA | 2. | Aa |
| 3. | aa | 4. | Cannot be determined |
Subtopic: Pedigree Analysis: More Examples |
74%
Level 2: 60%+
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Consider the inheritance of the trait as shown in the pedigree given above:
| Assertion(A): | The mode of inheritance cannot be X linked recessive. |
| Reason(R): | The father of the affected female does not have the disease. |
| 1. | (A) is true, (R) is true, (R) explains (A) |
| 2. | (A) is true, (R) is true, (R) does not explain (A) |
| 3. | (A) is true, (R) is false |
| 4. | (A) is false, (R) is true |
Subtopic: Pedigree Analysis: Problem Solving |
55%
Level 3: 35%-60%
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Regarding the features of autosomal recessive inheritance
| Statement(A): | Affected individuals never appear among the offspring of unaffected parents |
| Statement(B): | Affected offspring include only males |
| 1. | (A) is correct, (B) is correct |
| 2. | (A) is correct, (B) is incorrect |
| 3. | (A) is incorrect, (B) is correct |
| 4. | (A) is incorrect, (B) is incorrect |
Subtopic: Pedigree Analysis: Basics | Mendelian Disorders |
64%
Level 2: 60%+
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A father affected with an X-linked recessive disorder will have no affected children; all daughters will be carriers. This conclusion is valid only if:
1. The mother is homozygous normal \((X^AX^A)\)
2. The mother is phenotypically normal (carrier status unknown).
1. The mother is homozygous normal \((X^AX^A)\)
2. The mother is phenotypically normal (carrier status unknown).
Subtopic: Pedigree Analysis: Problem Solving | Mendelian Disorders |
Level 4: Below 35%
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A female with normal vision has a colour blind son who also has haemophilia.
The female's father did not have haemophilia or colour blindness.
Considering both colour blindness and haemophilia are X-linked recessive traits, what is the genotype of the female?
1. \(X^{BH}X^{BH}\)
2. \(X^{BH}X^{bh}\)
3. \(X^{bh}X^{bh}\)
4. \(X^{Bh}X^{bH}\)
The female's father did not have haemophilia or colour blindness.
Considering both colour blindness and haemophilia are X-linked recessive traits, what is the genotype of the female?
1. \(X^{BH}X^{BH}\)
2. \(X^{BH}X^{bh}\)
3. \(X^{bh}X^{bh}\)
4. \(X^{Bh}X^{bH}\)
Subtopic: Mendelian Disorders |
69%
Level 2: 60%+
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During genetic crosses, which recombination frequency value indicates that two genes assort independently and show no linkage?
1. 0
2. 0.25
3. 0.5
4. 0.75
1. 0
2. 0.25
3. 0.5
4. 0.75
Subtopic: Linkage Types | Recombination & Gene Mapping |
Level 4: Below 35%
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Q. No.
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