Temperature can be expressed as a derived quantity in terms of any of the following:

In $$\(S= a+bt+ct^2,~S\)  is measured in metres and \(t\) in seconds. The unit of \(c\) will be:

Given the equation \(\left(P+\frac{a}{V^2}\right)(V-b)=\text {constant}\). The units of \(a\) will be: (where \(P\) is pressure and \(V\) is volume)
1. \(\text{dyne} \times \text{cm}^5\)
2. \(\text{dyne} \times \text{cm}^4\)
3. \(\text{dyne} / \text{cm}^3\)
4. \(\text{dyne} / \text{cm}^2\)

The velocity \(v\) of a particle at time \(t\) is given by \({v}={at}+\frac{{b}}{{t}+{c}}.\) The dimensions of \({a}\), \({b}\), and \({c}\) are respectively:
1. \( {\left[{LT}^{-2}\right],[{L}],[{T}]} \)
2. \( {\left[{L}^2\right],[{T}] \text { and }\left[{LT}^2\right]} \)
3. \( {\left[{LT}^2\right],[{LT}] \text { and }[{L}]} \)
4. \( {[{L}],[{LT}], \text { and }\left[{T}^2\right]}\)

The position of a particle at time \(t\) is given by the relation \({x}({t})=\left(\frac{{v}_0}{\alpha}\right)\left(1-{e}^{-\alpha {t}}\right)\), where \(v_0\)${\mathrm{}}_{}$ is a constant and \(\alpha >0\). The dimensions of \(v_0\) and \(\alpha\) are respectively:
1. \(\left[M^0L^{1}T^{-1}\right]~\text{and}~\left[T^{-1}\right]\)
2. \(\left[M^0L^{1}T^{0}\right]~\text{and}~\left[T^{-1}\right]\)
3. \(\left[M^0L^{1}T^{-1}\right]~\text{and}~\left[LT^{-1}\right]\)
4. \(\left[M^0L^{1}T^{-1}\right]~\text{and}~\left[T\right]\)

For the expression, \(10^{(at+3)}\), the dimensions of \(a\) will be:
1. \(\left[M^0L^0T^{0}\right]\)
2. \(\left[M^0L^0T^{1}\right]\)
3. \(\left[M^0L^0T^{-1}\right]\)
4. None of these

The displacement (\(Y\)) as a function of position (\(x\)) and time (\(t\)) is given as \(Y= Ae^{(bx+Ct)}\). Which of the following expressions has dimensions different from others?

The quantities \(A\) and \(B\) are related by the relation, \(m= \frac{A}{B}\), where \(m\) is the linear density and \(A\) is the force. The dimensions of \(B\) are of:

If \(\int \frac{d x}{\sqrt{a^2-x^2}}=a^n \sin ^{-1} \frac{x}{a}\) is dimensionally correct, then the value of \(n\) will be: