Q. No.A true-breeding plant is:
| 1. | one that is able to breed on its own |
| 2. | produced due to cross-pollination among unrelated plants |
| 3. | near homozygous and produces offspring of its own kind |
| 4. | always homozygous recessive in its genetic constitution |
Subtopic: Â Monohybrid Cross: 1 |
 66%
Level 2: 60%+
NEET - 2016
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Alleles are:
1. different phenotype
2. true breeding homozygotes
3. different molecular forms of a gene
4. heterozygotes
Subtopic: Â Monohybrid Cross: 1 |
 82%
Level 1: 80%+
NEET - 2015
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A heterozygous pea plant with violet flowers was crossed with a homozygous pea plant with white flowers. Violet is dominant over white. Which one of the following represents the expected combinations among 40 progenies formed?
1. 30 produced violet and 10 produced white flowers
2. 20 produced violet and 20 produced white flowers.
3. All 40 produced violet flowers
4. All 40 produced white flowers
1. 30 produced violet and 10 produced white flowers
2. 20 produced violet and 20 produced white flowers.
3. All 40 produced violet flowers
4. All 40 produced white flowers
Subtopic: Â Monohybrid Cross: 1 |Â Monohybrid Cross: Further Understanding |
 72%
Level 2: 60%+
NEET - 2023
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The production of gametes by the parents the formation of zygotes, the F1 and F2 plants can be understood using
| 1. | Pie diagram | 2. | A pyramid diagram |
| 3. | Punnett square | 4. | Wenn diagram |
Subtopic: Â Monohybrid Cross: 1 |
 95%
Level 1: 80%+
NEET - 2021
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A tall true breeding garden pea plant is crossed with a dwarf true breeding garden pea plant. When the F1 plants were selfed, the resulting genotypes were in the ratio of:
1. 1:2:1 :: Tall heterozygous : Tall homozygous : Drawf
2. 3:1 :: Tall : Dwarf
3. 3:1:: Dwarf : Tall
4. 1:2:1:: Tall homozygous : Tall heterozygous : Dwarf
2. 3:1 :: Tall : Dwarf
3. 3:1:: Dwarf : Tall
4. 1:2:1:: Tall homozygous : Tall heterozygous : Dwarf
Subtopic: Â Monohybrid Cross: 1 |
 75%
Level 2: 60%+
NEET - 2016
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Select the correct statement:
1. Franklin Stahl coined the term "linkage".
2. Punnett square was developed by a British scientist.
3. Spliceosomes take part in translation.
4. Transduction was discovered by S. Altman.
1. Franklin Stahl coined the term "linkage".
2. Punnett square was developed by a British scientist.
3. Spliceosomes take part in translation.
4. Transduction was discovered by S. Altman.
Subtopic: Â Monohybrid Cross: 1 |
 86%
Level 1: 80%+
NEET - 2018
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Match List-I and List-II:
Choose the correct answer from the options given below:
| List-I | List-II | ||
| A. | Two or more alternative forms of a gene | I. | Back Cross |
| B. | Cross of F1 progeny with homozygous recessive parent | II. | Ploidy |
| C. | Cross of F1 progeny with any of the parents | III. | Allele |
| D. | Number of chromosome sets in plant |
IV. | Test cross |
| 1. | A-II, B-I, C-III, D-IV | 2. | A-III, B-IV, C-I, D-II |
| 3. | A-IV, B-III, C-II, D-I | 4. | A-I, B-II, C-III, D-IV |
Subtopic: Â Monohybrid Cross: 1 |
 89%
Level 1: 80%+
NEET - 2024
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A cross between tall plants was made resulting in offspring of tall and dwarf plants with ratio 3 : 1. The genotype(s) of both parents are:
1. TT and TT
2. Tt and tt
3. Tt and Tt
4. tt and tt
1. TT and TT
2. Tt and tt
3. Tt and Tt
4. tt and tt
Subtopic: Â Monohybrid Cross: 1 |Â Monohybrid Cross: Further Understanding |
 77%
Level 2: 60%+
NEET - 2024
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Which one of the following can be explained as the basis of Mendel's Law of dominance?
Choose the correct answer from the options given below:
| A: | Out of one pair of factors, one is dominant and the other is recessive. |
| B: | Alleles do not show any expression and both the characters appear as such in F2 generation. |
| C: | Factors occur in pairs in normal diploid plants. |
| D: | The discrete unit controlling a particular character is called factor. |
| E: | The expression of only one of the parental characters is found in a monohybrid cross. |
| 1. | A, C, D and E only | 2. | B, C and D only |
| 3. | A, B, C, D and E | 4. | A, B and C only |
Subtopic: Â Monohybrid Cross: 1 |
 68%
Level 2: 60%+
NEET - 2024
Hints
F2 generation in a Mendelian cross showed that both genotypic and phenotypic ratios are same as 1: 2: 1. It represents a case of:
1. Co-dominance
2. Dihybrid crosses
3. Monohybrid crosses with complete dominance
4. Monohybrid crosses with incomplete dominance
Subtopic: Â Monohybrid Cross: 1 |
 73%
Level 2: 60%+
AIPMT - 2012
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