The least count of vernier callipers is \(0.1\) mm. The main scale reading before the zero of the vernier scale is \(10\), and the zeroth division of the vernier scale coincides with any main scale division. If the value of one main scale division is \(1\) mm, the measured value should be expressed as:
1. \(0.010\) cm
2. \(0.001\) cm
3. \(0.1\) cm
4. \(1.00\) cm

Subtopic:  Measurement & Measuring Devices |
Level 3: 35%-60%
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A screw gauge of pitch \(0.5\) mm is used to measure the diameter of uniform wire of length \(6.8\) cm, the main scale reading is \(1.5\) mm and circular scale reading is \(7\). The calculated curved surface area of wire to the appropriate significant figures is:
[Screw gauge has \(50\) divisions on the circular scale]
1. \(6.8\) cm2
2. \(3.4\) cm2
3. \(3.9\) cm2
4. \(2.4\) cm2
Subtopic:  Measurement & Measuring Devices |
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Level 3: 35%-60%
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The Vernier constant of Vernier callipers is \(0.1\) mm and it has zero error of \((-0.05)\) cm. While measuring the diameter of a sphere, the main scale reading is \(1.7\) cm and the coinciding Vernier division is \(5.\) The corrected diameter will be:
1. \(1.75 \times 10^{-2}\) cm
2. \(180 \times 10^{-2}\) cm
3. \(175 \times 10^{-2}\) cm
4. \(17.5 \) cm
Subtopic:  Measurement & Measuring Devices |
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Level 2: 60%+
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A travelling microscope has \(20\) divisions per cm on the main scale while its Vernier scale has total \(50\) divisions and \(25\) Vernier scale divisions are equal to \(24\) main scale divisions, what is the least count of the travelling microscope?
1. \(0.001\) cm
2. \(0.002\) mm
3. \(0.002\) cm
4. \(0.005\) cm
Subtopic:  Measurement & Measuring Devices |
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Level 2: 60%+
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When the circular scale of a screw gauge completes \(2\) rotations, it covers \(1\) mm over the pitch scale. The total number of circular scale divisions is \(50.\) The least count of the screw gauge in metres is:
1. \(10^{-4}\)
2. \(10^{-5}\)
3. \(10^{-2}\)
4. \(10^{-3}\)

Subtopic:  Measurement & Measuring Devices |
 57%
Level 3: 35%-60%
NEET - 2022
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A screw gauge has the least count of \(0.01~\text{mm}\) and there are \(50\) divisions in its circular scale. The pitch of the screw gauge is:

1. \(0.25~\text{mm}\) 2. \(0.5~\text{mm}\)
3. \(1.0~\text{mm}\) 4. \(0.01~\text{mm}\)
Subtopic:  Measurement & Measuring Devices |
 85%
Level 1: 80%+
NEET - 2020
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The main scale of a vernier calliper has \(n\) divisions/cm. \(n\) divisions of the vernier scale coincide with \((n-1)\) divisions of the main scale. The least count of the vernier calliper is:

1. \(\dfrac{1}{(n+1)(n-1)}\) cm 2. \(\dfrac{1}{n}\) cm
3. \(\dfrac{1}{n^{2}}\) cm 4. \(\dfrac{1}{(n)(n+1)}\) cm
Subtopic:  Measurement & Measuring Devices |
 53%
Level 3: 35%-60%
NEET - 2019
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Which of the following is the most precise device for measuring length?

1. a vernier calliper with \(20\) divisions on the sliding scale.
2. a screw gauge of pitch \(1\) mm and \(100\) divisions on the circular scale.
3. an optical instrument that can measure the length within a wavelength of light.
4. both (1) and (2)

Subtopic:  Measurement & Measuring Devices |
Level 3: 35%-60%
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A student measures the thickness of a human hair by looking at it through a microscope of magnification \(100.\) He makes \(20\) observations and finds that the average width of the hair in the field of view of the microscope is \(3.5 ~\text{mm}.\) The thickness of the hair is:
1. \(0.035~\text{mm}\)
2. \(0.0035 ~\text {mm}\)
3. \(0.35 ~\text{mm}\)
4. \(3.5 ~\text{mm}\)

Subtopic:  Measurement & Measuring Devices |
 60%
Level 2: 60%+
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A vernier calipers has \(1~\text{mm}\) marks on the main scale. It has \(20\) equal divisions on the vernier scale which match with \(16\) main scale divisions. The least count of this vernier calipers is:
1. \(0.02~\text{mm}\) 2. \(0.05~\text{mm}\)
3. \(0.10~\text{mm}\) 4. \(0.20~\text{mm}\)
Subtopic:  Measurement & Measuring Devices |
 69%
Level 2: 60%+
NEET - 2024
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