premium feature crown icon
Unlock IMPORTANT QUESTION
This question was bookmarked by 5 NEET 2025 toppers during their NEETprep journey. Get Target Batch to see this question.
✨ Perfect for quick revision & accuracy boost
Buy Target Batch
Access all premium questions instantly
Assertion (A): 1 g O2 and 1 g O3  have an equal number of oxygen atoms.
Reason (R): O2  and  O3  have different molar masses.
 
1. Both (A) and (R) are True and (R) is the correct explanation of (A).
2. Both (A) and (R) are True but (R) is not the correct explanation of (A).
3. (A) is True but (R) is False.
4. (A) is False but (R) is True.
Subtopic:  Moles, Atoms & Electrons |
Level 3: 35%-60%
Hints
Links

premium feature crown icon
Unlock IMPORTANT QUESTION
This question was bookmarked by 5 NEET 2025 toppers during their NEETprep journey. Get Target Batch to see this question.
✨ Perfect for quick revision & accuracy boost
Buy Target Batch
Access all premium questions instantly

Match the following physical quantities with units.

Physical quantity Unit
A. Molarity (i).  mol kg–1 
B.  Molality (ii). mol L–1
C.  Pressure (iii).  Candella
D. Luminous intensity (iv). Pascal

Codes:

A B C D
1. (i) (iv) (ii) (iii)
2. (ii) (i) (iv) (iii)
3. (i) (iv) (iii) (ii)
4. (iv) (i) (iii) (ii)
Subtopic:  Introduction |
 94%
Level 1: 80%+
Hints

premium feature crown icon
Unlock IMPORTANT QUESTION
This question was bookmarked by 5 NEET 2025 toppers during their NEETprep journey. Get Target Batch to see this question.
✨ Perfect for quick revision & accuracy boost
Buy Target Batch
Access all premium questions instantly
The correct match is:
List I List II
a. Micro i.  10-15 m
b. Mega ii.  10-6 m
c. Giga iii.  106 m
d. Femto iv.  109 m
Codes:
a b c d
1. i iv iii ii
2. iii iv ii i
3. ii iii iv i
4. i iii iv ii
Subtopic:  Introduction |
 86%
Level 1: 80%+
Hints

advertisementadvertisement

premium feature crown icon
Unlock IMPORTANT QUESTION
This question was bookmarked by 5 NEET 2025 toppers during their NEETprep journey. Get Target Batch to see this question.
✨ Perfect for quick revision & accuracy boost
Buy Target Batch
Access all premium questions instantly

At 100 ºC and 1 atm, if the density of liquid water is 1.0 g cm–3 and that of water vapor is 0.0006 g cm-3, then the volume occupied by water molecules in 1 litre of steam at that temperature will be:

1. 6 cm 2. 60 cm3
3. 0.6 cm3  4. 0.06 cm3
Subtopic:  Moles, Atoms & Electrons |
 60%
Level 2: 60%+
Hints
Links

premium feature crown icon
Unlock IMPORTANT QUESTION
This question was bookmarked by 5 NEET 2025 toppers during their NEETprep journey. Get Target Batch to see this question.
✨ Perfect for quick revision & accuracy boost
Buy Target Batch
Access all premium questions instantly

At STP, the density of CCl4 vapour in g/L will be closest to: 

1. 8.67

2. 6.87

3. 3.67

4. 4.26

Subtopic:  Concentration Based Problem |
 76%
Level 2: 60%+
Hints
Links

premium feature crown icon
Unlock IMPORTANT QUESTION
This question was bookmarked by 5 NEET 2025 toppers during their NEETprep journey. Get Target Batch to see this question.
✨ Perfect for quick revision & accuracy boost
Buy Target Batch
Access all premium questions instantly

A reading on Fahrenheit scale is 200°F. The same reading on celsius scale will be :
1. 40°C
2. 94°C
3. 93°C
4. 30°C

Subtopic:  Introduction |
 69%
Level 2: 60%+
Hints

advertisementadvertisement

premium feature crown icon
Unlock IMPORTANT QUESTION
This question was bookmarked by 5 NEET 2025 toppers during their NEETprep journey. Get Target Batch to see this question.
✨ Perfect for quick revision & accuracy boost
Buy Target Batch
Access all premium questions instantly

The numbers 234,000 and 6.0012 can be represented in scientific notation as:

1. 2.34×10-9and6×103

2. 0.234 ×10-6 and 60012×10-9

3. 2.34×10-9and 6.0012×10-9

4. 2.34×105 and 6.0012×100

Subtopic:  Introduction |
 85%
Level 1: 80%+
Hints

premium feature crown icon
Unlock IMPORTANT QUESTION
This question was bookmarked by 5 NEET 2025 toppers during their NEETprep journey. Get Target Batch to see this question.
✨ Perfect for quick revision & accuracy boost
Buy Target Batch
Access all premium questions instantly

ln the final answer of the expression \(\large{\frac{(29.2-20.2)\times(1.79\times10^5)}{1.37}}\)
the number of significant figures after solving the expression is:

1. 2 2. 4
3. 6 4. 7
Subtopic:  Introduction |
 61%
Level 2: 60%+
Hints

premium feature crown icon
Unlock IMPORTANT QUESTION
This question was bookmarked by 5 NEET 2025 toppers during their NEETprep journey. Get Target Batch to see this question.
✨ Perfect for quick revision & accuracy boost
Buy Target Batch
Access all premium questions instantly
The number of significant figures in the numbers 5005, 500.0, and 126,000 are, respectively: 
1. 2, 4, and 3 
2. 4, 1, and 3 
3. 4, 4, and 6 
4. 4, 4, and 3 
Subtopic:  Introduction |
 60%
Level 2: 60%+
Hints

advertisementadvertisement

premium feature crown icon
Unlock IMPORTANT QUESTION
This question was bookmarked by 5 NEET 2025 toppers during their NEETprep journey. Get Target Batch to see this question.
✨ Perfect for quick revision & accuracy boost
Buy Target Batch
Access all premium questions instantly

If 0.5 moles of BaCl2 is reacted with 0.2 moles of Na3PO4 then the maximum moles of Ba3(PO4)2 formed is:

1. 0.33 2. 0.25
3. 0.10 4. 0.52
Subtopic:  Limiting Reagent |
 73%
Level 2: 60%+
Hints
Links