To produce an instantaneous displacement current of \(2~\text{mA}\) in the space between the parallel plates of a capacitor of capacitance \(4~\mu\text{F}\), the rate of change of applied variable potential difference \(\left(\dfrac{dV}{dt}\right) \) must be:
1. \( 800~ \text{V} / \text{s} \)
2. \( 500~ \text{V} / \text{s} \)
3. \( 200~ \text{V} / \text{s} \)
4. \( 400 ~\text{V} / \text{s}\)
Subtopic:  Displacement Current |
 80%
Level 1: 80%+
NEET - 2023
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A capacitor of capacitance \(C\) is connected across an AC source of voltage \(V\), given by;
\(V=V_0 \sin \omega t\)
The displacement current between the plates of the capacitor would then be given by:
1. \( I_d=\dfrac{V_0}{\omega C} \sin \omega t \) 2. \( I_d=V_0 \omega C \sin \omega t \)
3. \( I_d=V_0 \omega C \cos \omega t \) 4. \( I_d=\dfrac{V_0}{\omega C} \cos \omega t\)
Subtopic:  Displacement Current |
 60%
Level 2: 60%+
NEET - 2021
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A parallel plate capacitor of capacitance \(20~\mu\text{F}\) is being charged by a voltage source whose potential is changing at the rate of \(3~\text{V/s}.\) The conduction current through the connecting wires, and the displacement current through the plates of the capacitor would be, respectively:

1. zero, zero 2. zero, \(60~\mu\text{A}\)
3. \(60~\mu\text{A},\) \(60~\mu\text{A}\) 4. \(60~\mu\text{A},\) zero
Subtopic:  Displacement Current |
 72%
Level 2: 60%+
NEET - 2019
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