- 1(current)
Q. No.The period of oscillation of a mass \(M\) suspended from a spring of negligible mass is \(T\). If along with it, another mass \(M\) is also suspended, the period of oscillation will now be:
1. \(T\)
2. \(\frac{T}{\sqrt{2}}\)
3. \(2T\)
4. \(\sqrt{2}T\)
1. \(T\)
2. \(\frac{T}{\sqrt{2}}\)
3. \(2T\)
4. \(\sqrt{2}T\)
Subtopic: Spring mass system |
81%
Level 1: 80%+
AIPMT - 2010
Hints
The time period of a mass suspended from a spring is \(T\). If the spring is cut into four equal parts and the same mass is suspended from one of the parts, then the new time period will be:
1. \(\frac{T}{4}\)
2. \(T\)
3. \(\frac{T}{2}\)
4. \(2T\)
Subtopic: Spring mass system |
75%
Level 2: 60%+
AIPMT - 2003
Hints
A spring elongates by a length 'L' when a mass 'M' is suspended to it. Now a tiny mass 'm' is attached to the mass 'M' and then released. The new time period of oscillation will be:
1. \(2 \pi \sqrt{\frac{\left(\right. M + m \left.\right) l}{Mg}}\)
2. \(2 \pi \sqrt{\frac{ml}{Mg}}\)
3. \(2 \pi \sqrt{L / g}\)
4. \(2 \pi \sqrt{\frac{Ml}{\left(\right. m + M \left.\right) g}}\)
Subtopic: Spring mass system |
61%
Level 2: 60%+
AIPMT - 1999
Hints
The frequency of a spring is \(n\) after suspending mass \(M.\) Now, after mass \(4M\) mass is suspended from the spring, the frequency will be:
| 1. | \(2n\) | 2. | \(n/2\) |
| 3. | \(n\) | 4. | none of the above |
Subtopic: Spring mass system |
83%
Level 1: 80%+
AIPMT - 1998
Hints
- 1(current)
Q. No.
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