\(1~\text g\) of water of volume \(1~\text{cm}^3\) at \(100^\circ \text{C}\) is converted into steam at the same temperature under normal atmospheric pressure \(\approx 1\times10^{5}~\text{Pa}.\) The volume of steam formed equals \(1671~\text{cm}^3.\) If the specific latent heat of vaporization of water is \(2256~\text{J/g},\) the change in internal energy is:

1. \(2423~\text J\) 2. \(2089~\text J\)
3. \(167~\text J\) 4. \(2256~\text J\)
Subtopic:  First Law of Thermodynamics |
 67%
Level 2: 60%+
NEET - 2019
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A sample of \(0.1\) g of water at \(100^{\circ}\mathrm{C}\) and normal pressure (\(1.013 \times10^5\) N m–2) requires \(54\) cal of heat energy to convert it into steam at \(100^{\circ}\mathrm{C}\). If the volume of the steam produced is \(167.1\) cc, then the change in internal energy of the sample will be:

1. \(104.3\) J 2. \(208.7\) J
3. \(42.2\) J 4. \(84.5\) J
Subtopic:  First Law of Thermodynamics |
 70%
Level 2: 60%+
NEET - 2018
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