The standard enthalpy of vaporization for water at 100 oC is 40.66 kJ mol–1. The internal energy of vaporization of water at 100 oC (in kJ mol–1) is:
(Assume water vapour behaves like an ideal gas.)
| 1. | +37.56 | 2. | –43.76 |
| 3. | +43.76 | 4. | +40.66 |
Calculate the H–H bond dissociation energy from the following reaction:
4H(g) → 2H₂(g) ΔH = −869.6 kJ
1. -869.6 kJ
2. +434.8kJ
3. +217.4kJ
4. -434.8 kJ
Consider the following processes:
∆H (kJ/mol)
½ A → B + 150
3B → 2C + D –125
E + A → 2D +350
For B + D → E + 2C, ∆H will be:
1. 325 kJ/mol
2. 525 kJ/mol
3. –175 kJ.mol
4. –325 kJ/mol
The following two reactions are known
The value of H for the following reaction
is:
1. -43.3 kJ
2. -10.3 kJ
3. +6.2 kJ
4. +10.3 kJ
The difference between enthalpy (∆H) and internal energy (∆E) for the given below reaction,
under constant temperature, is:
\(C_{3} H_{8} \left(\right. g \left.\right) + 5 O_{2} \left(\right. g \left.\right) \rightarrow 3 CO_{2} \left(\right. g \left.\right) + 4 H_{2} O \left(\right. l \left.\right)\)
| 1. | + RT | 2. | – 3RT |
| 3. | + 3RT | 4. | – RT |
For the given reaction
, the heat of formations of are -188 kJ/mol & -286 KJ/mol respectively. The change in the enthalpy of the reaction will be:
1. – 196 kJ/mol
2. + 196 kJ/mol
3. + 948 kJ/mol
4. – 948 kJ/mol
The enthalpy of \(CH_4 + \dfrac{1}{2 }O_2 \rightarrow\ CH_3OH\) is negative. If enthalpy of combustion of methane and \(CH_3OH\) are x and y, respectively, then which of the following relations is correct?
| 1. | x > y | 2. | x < y |
| 3. | x = y | 4. | x ≥ y |
For the reaction,
C2H5OH(l) + 3O2(g) →2CO2(g) + 3H2O(l)
which one is true?
| 1. | ∆H = ∆E – RT | 2. | ∆H = ∆E + RT |
| 3. | ∆H = ∆E + 2RT | 4. | ∆H = ∆E – 2RT |
Which of the following statements are true for a cyclic process?
| a. | W = 0 | b. | ∆E = 0 |
| c. | ∆H = 0 | d. | ∆E ≠ 0 |
1. a, b
2. b, c
3. c, d
4. a, d
If a system is expanded under adiabatic process, then:
1. Temperature increases
2. ∆E decreases
3. ∆E increases
4. None of the above