Q. No.The effective capacity of the network between terminals \({A}\) and \(B\) is:
| 1. | \(6~\mu\text{F}\) | 2. | \(20~\mu\text{F}\) |
| 3. | \(3~\mu\text{F}\) | 4. | \(10~\mu\text{F}\) |
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Three uncharged capacitors of capacities \(C_1, C_2~\text{and}~C_3 \) are connected to one another as shown in the figure.
If points \(A, B, \text{and } D,\) are at potential \(V_1, V_2 ~\text{and}~V_3\) then the potential at \(O\) will be:
| 1. | \(\dfrac{V_1C_1+V_2C_2+V_3C_3}{C_1+C_2+C_3}\) | 2. | \(\dfrac{V_1+V_2+V_3}{C_1+C_2+C_3}\) |
| 3. | \(\dfrac{V_1(V_2+V_3)}{C_1(C_2+C_3)}\) | 4. | \(\dfrac{V_1V_2V_3}{C_1C_2C_3}\) |
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Three capacitors each of capacity \(4\) µF are to be connected in such a way that the effective capacitance is \(6\) µF. This can be done by:
| 1. | connecting all of them in a series. |
| 2. | connecting them in parallel. |
| 3. | connecting two in series and one in parallel. |
| 4. | connecting two in parallel and one in series. |
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Three capacitors of capacitances \(3~\mu\text{F}\), \(9~\mu\text{F}\) and \(18~\mu\text{F}\) are connected once in series and another time in parallel. The ratio of equivalent capacitance in the two cases \(\frac{C_s}{C_p}\) will be:
1. \(1:15\)
2. \(15:1\)
3. \(1:1\)
4. \(1:3\)
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Two capacitors of capacitance \(6~\mu\text{F}\) and \(3~\mu\text{F}\) are connected in series with battery of \(30~\text{V}\). The charge on \(3~\mu\text{F}\) capacitor is:
1. \( 3 ~\mu\text{C}\)
2. \( 1.5 ~\mu\text{C}\)
3. \( 60~\mu\text{C}\)
4. \( 900~\mu\text{C}\)
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The equivalent capacitance across \(A\) and \(B\) in the given figure is:
| 1. | \( \dfrac{3}{2}C\) | 2. | \({C}\) |
| 3. | \( \dfrac{2}{3}{C}\) | 4. | \( \dfrac{5}{3}C\) |
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Three capacitors each of capacitance \(C\) and of breakdown voltage \(V\) are joined in series. The capacitance and breakdown voltage of the combination will be:
1. \(\frac{C}{3}, \frac{V}{3}\)
2. \(3C, \frac{V}{3}\)
3. \(\frac{C}{3}, 3V\)
4. \(3C, 3V\)
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The equivalent capacitance of the following arrangement is:
1. \(18~\mu \text{F}\)
2. \(9~\mu \text{F}\)
3. \(6~\mu \text{F}\)
4. \(12~\mu \text{F}\)
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The equivalent capacitance between points \(a\) and \(b\) in the network shown below is:
1. \(5~\text{C}\)
2. \(4~\text{C}\)
3. \(3~\text{C}\)
4. \(2~\text{C}\)
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A capacitor of capacity \(C_1\) is charged up to \(V\) volt and then connected to an uncharged capacitor \(C_2\). Then final P.D. across each will be:
1. \(\frac{C_{2} V}{C_{1} + C_{2}}\)
2. \(\frac{C_{1} V}{C_{1} + C_{2}}\)
3. \(\left(1 + \frac{C_{2}}{C_{1}}\right)\)
4. \(\left(1 - \frac{C_{2}}{C_{1}} \right) V\)
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